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Top Forums Shell Programming and Scripting How to copy a directory without specific files? Post 302910701 by bakunin on Sunday 27th of July 2014 01:35:02 PM
Old 07-27-2014
Quote:
Originally Posted by reddyr
I need to copy a huge directory with thousands of files onto another directory but without *.WMV files (and without *.wmv - perhaps we need to use *.[wW][mM][vV])
Use "find":

Code:
cd /path/to/sourcedir
find . ! -name "*.[wW][mM][vV]" -exec cp {} /path/to/targetdir \;

Note that you have to change into the directory first, because "find" will find ./file, which can used in the cp-command directly, while with an absolute path you'd get the absolute path /path/to/sourcedir/file which you'd need to modify first.

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
 

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Dpkg::Path(3)							   libdpkg-perl 						     Dpkg::Path(3)

NAME
Dpkg::Path - some common path handling functions DESCRIPTION
It provides some functions to handle various path. METHODS
get_pkg_root_dir($file) This function will scan upwards the hierarchy of directory to find out the directory which contains the "DEBIAN" sub-directory and it will return its path. This directory is the root directory of a package being built. If no DEBIAN subdirectory is found, it will return undef. relative_to_pkg_root($file) Returns the filename relative to get_pkg_root_dir($file). guess_pkg_root_dir($file) This function tries to guess the root directory of the package build tree. It will first use get_pkg_root_dir(), but it will fallback to a more imprecise check: namely it will use the parent directory that is a sub-directory of the debian directory. It can still return undef if a file outside of the debian sub-directory is provided. check_files_are_the_same($file1, $file2, $resolve_symlink) This function verifies that both files are the same by checking that the device numbers and the inode numbers returned by stat()/lstat() are the same. If $resolve_symlink is true then stat() is used, otherwise lstat() is used. canonpath($file) This function returns a cleaned path. It simplifies double //, and remove /./ and /../ intelligently. For /../ it simplifies the path only if the previous element is not a symlink. Thus it should only be used on real filenames. $newpath = resolve_symlink($symlink) Return the filename of the file pointed by the symlink. The new name is canonicalized by canonpath(). my $cmdpath = find_command($command) Return the path of the command if available on an absolute or relative path or on the $PATH, undef otherwise. my $control_file = get_control_path($pkg, $filetype) Return the path of the control file of type $filetype for the given package. my @control_files = get_control_path($pkg) Return the path of all available control files for the given package. AUTHOR
Raphael Hertzog <hertzog@debian.org>. 1.16.0.3 2012-04-17 Dpkg::Path(3)
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