The only safe way for an open entry point into your code is to state and then test ONLY what you will allow.
Blocking what you will not allow is impossible, logically, because the number of wrong or potentially bad inputs is infinite.
Create a list of what is allowed. Check to see that your entry is in there:
Simple minded example, /etc/passwd is the list of allowed users and has : as a field separator; username is field #1, hence the printf format "%s:"
Im facing problem in assigning value of eval array variable as normal variable..
x=0
eval DATA${x}="FJSVcpcu"
x=`expr $x + 1`
eval DATA${x}="FJSVcsr"
if x=0, type -> eval echo \$DATA$x , its give me FJSVcpcu
i want assign this value into an variable as
variable=`eval echo... (3 Replies)
Hello,
I have a script that does an scp to a server and then gets the number of process running on that server, the o/P should be stored in a variable for further processing
eval `echo "ssh -q $Infa_user@$host 'csh -c $CMD '"`
where
CMD="ps -ef | grep -i ${INFA_REPO} | grep -v grep | wc... (2 Replies)
Help !!
First, Thanks in Advance
Here is what I have
I have an environment Variable, let's call it v_VALUE.
v_VALUE="\$ORACLE_HOME/bin" Hence, the location is ORACLE_HOME is not evaluated. ORACLE_HOME happens to be /app/oracle/product/10.1.2
I need a method of returning the... (1 Reply)
Hi,
i have an issue with eval and variable assignment.
1) i have a date value in a variable and that date is part of a filename,
var1=20100331
file1=${var1}-D1-0092.xml.zip
file2=${var2}-D2-0092.xml.zip
file3=${var3}-D3-0092.xml.zip
i am passing the above variables to a script via... (11 Replies)
Hi Gurus,
I am having 2 parameters as below
parm1=value1
parm2=parm1
I want to evaluate parm1 value using eval echo \$$parm2 and later i want to assign this value to other variable which i will be using in if statement like :
if ]; then
do this.......
fi
could you please suggest... (5 Replies)
According to the POSIX specifications eval is a special shell built-in, which should imply that variable assignments specified together with it should remain in effect after the built-in completes. Thus one would expect IFS to be changed after this:
var=$'a\nb c'
$ IFS=$'\n' eval '
for i in... (4 Replies)
background : Solaris, ksh
metresult="ooo
> pp"
ts=89
eval append_${ts}="$metresult"
bash: pp: command not found
I want to create a variable which has in a part of its name a dynamically-established number (stored in another variable) usually I do this with eval command. The problem I... (5 Replies)
pattern1=book
{
x=1
eval echo \$pattern$x
}
book (this is the output)
But when I assign a variable to the output of the eval it doesn't work unless I prefix 2 times backslash before $ as shown below.
{
a=`eval echo \\$pattern$x`
echo $a
}
book
Why here twice "\" has to be... (3 Replies)
Discussion started by: ravisingh
3 Replies
LEARN ABOUT DEBIAN
partimaged-passwd
partimaged-passwd(8) Partition Image Server Configuration partimaged-passwd(8)NAME
partimaged-passwd - Manage partimaged user accounts
SYNTAX
partimaged-passwd [-Dhl] username password
partimaged-passwd [-Dhl] username
DESCRIPTION
partimaged can either authenticate against local user accounts (This needs access to /etc/shadow. As this is a potential security risk this
method is not recommended) or its own password database in /etc/partimaged/passwd.db. To simplify the management of the partimaged user
database this tool was written. It allows to easily add and remove users or list the users in the database. All users in this database are
allowed to access the partimaged server.
OPTIONS -D username
Delete the specified user from the password file.
-l List users in password file and exit.
-h Output help information and exit.
FILES
/etc/partimaged/passwd.db
AUTHORS
Michael Biebl <biebl@debian.org>
SEE ALSO partimaged(8), partimagedusers(5), partimage(1)Michael Biebl <biebl@teco.edu> 0.1 partimaged-passwd(8)