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Top Forums Programming C++ : Base class member function not accessible from derived class Post 302910005 by anand.shah on Tuesday 22nd of July 2014 02:02:14 AM
Old 07-22-2014
C++ : Base class member function not accessible from derived class

Hello All,
I am a learner in C++. I was testing my inheritance knowledge with following piece of code.

Code:
#include <iostream>

using namespace std;

class base
{
	public :
		void display()
		{
			cout << "In base display()" << endl;
		}
		void display(int k)
		{
			cout << "In base display(int k)" << endl;
		}
};

class derived : public base
{
	public :
		void display()
		{
			cout << "In derive display()" << endl;
		}
};

int main()
{
	derived der;	
	der.display(50);
}


As far as I know it should compile without giving any error. But that is not the case as it is giving compilation error saying :-

Code:
StaticMember_1.cpp: In function ‘int main()':
StaticMember_1.cpp:30: error: no matching function for call to ‘derived::display(int)'
StaticMember_1.cpp:21: note: candidates are: void derived::display()

Can you guys help me out in finding why its giving error. there must be some concept here which I am missing.
Thanks in advance all of you.

Regards,
Anand Shah
 

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FBB::repeat(3bobcat)					      repeated function calls					      FBB::repeat(3bobcat)

NAME
FBB::repeat - call a (member) function a fixed number of times SYNOPSIS
#include <bobcat/repeat> DESCRIPTION
The FBB::repeat function template allows a function or member function to be called a certain number of times. The functions or member functions may define arguments. Arguments to these functions are specified when repeat is called, and are perfectly forwarded by the repeat function template to the (member) function called by repeat. The first argument of the repeat function template defines the number of times the (member) function must be called. The FBB::repeat function template are defined inline, allowing the compiler to `optimize away' the repeat function call itself. NAMESPACE
FBB All constructors, members, operators and manipulators, mentioned in this man-page, are defined in the namespace FBB. INHERITS FROM
- REPEAT FUNCTION TEMPLATE
The repeat function template is declared as: template <typename Counter, typename First, typename ...Params> void repeat(Counter counter, First &&first, Params &&...params); In this declaration, o Counter represents the counter's type. Usually an int or size_t. When calling repeat counter must be initialized to the number of times repeat must call the (member) function (see below); o First represents the prototype of a function or the name of a class. name of a class. Likewise, first either is the address (name) of the function to be called or the name of an object of class type First. In the latter case the object may or may not be a const object. o ...Params represents the set of parameter types of arguments which must be perfectly forwarded to the called function. If first rep- resents a class type object, the first argument must be the address of a member function of the class First. EXAMPLES
#include <iostream> #include <iterator> #include <algorithm> #include "../repeat" using namespace std; using namespace FBB; class Object { public: void member(int argc, char **argv) const; void member2(size_t &rept, int argc, char **argv); }; void Object::member(int argc, char **argv) const { cout << "member called "; copy(argv, argv + argc, ostream_iterator<char const *>(cout, " ")); } void Object::member2(size_t &rept, int argc, char **argv) { cout << "member2 called, iteration " << rept++ << " "; copy(argv, argv + argc, ostream_iterator<char const *>(cout, " ")); } void fun() { cout << "Fun called "; } int main(int argc, char **argv) { Object object; cout << " " "*** The number of arguments determines the repeat-count *** "; cout << "Fun without arguments: "; repeat(argc, fun); cout << "Object receiving argc and argv: "; repeat(argc, object, &Object::member, argc, argv); cout << "Object receiving argc and argv, showing the iteration count: "; size_t count = 0; repeat(argc, object, &Object::member2, count, argc, argv); Object const obj; cout << "Const Object receiving argc and argv: "; repeat(argc, obj, &Object::member, argc, argv); } FILES
bobcat/repeat - defines the class interface SEE ALSO
bobcat(7) BUGS
Be careful when using overloaded functions, as the template argument resolution mechanism may be unable to determine which function to call. If overloaded functions must be used, a static_cast is likely required to disambiguate your intentions. DISTRIBUTION FILES
o bobcat_3.01.00-x.dsc: detached signature; o bobcat_3.01.00-x.tar.gz: source archive; o bobcat_3.01.00-x_i386.changes: change log; o libbobcat1_3.01.00-x_*.deb: debian package holding the libraries; o libbobcat1-dev_3.01.00-x_*.deb: debian package holding the libraries, headers and manual pages; o http://sourceforge.net/projects/bobcat: public archive location; BOBCAT
Bobcat is an acronym of `Brokken's Own Base Classes And Templates'. COPYRIGHT
This is free software, distributed under the terms of the GNU General Public License (GPL). AUTHOR
Frank B. Brokken (f.b.brokken@rug.nl). libbobcat1-dev_3.01.00-x.tar.gz 2005-2012 FBB::repeat(3bobcat)
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