Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Bash: Getting first digit of a string
Top Forums Shell Programming and Scripting Bash: Getting first digit of a string Post 302909572 by daPeach on Thursday 17th of July 2014 04:14:22 PM
Old 07-17-2014
hi,

like RudiC using parameter expansion, but not format dependant:
Code:
$ string="abc-def-1.2.3"
$ digits=${string//[^[:digit:]]/}
$ echo ${digits::1} 
1

This User Gave Thanks to daPeach For This Post:
atsim
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Replace one digit by two digit using sed

Folks, Is there a simple way to replace one digit by two digit using sed. Example, mydigit1918_2006_8_8_lag1.csv should be mydigit1918_2006_08_08_lag01.csv. I tried this way, but doesn't work. echo mydigit1989_2006_8_8_lag1.csv|sed 's/]/0]/' Thank you, (5 Replies)
Discussion started by: Jae
5 Replies

2. Shell Programming and Scripting

How to convert a 2 digit to 4 digit

Hi All, How can i convert a number 24 to 0024 In the same way how can i convert 123 to 0123? All this has to be done inside a script Thanks in advance JS (6 Replies)
Discussion started by: jisha
6 Replies

3. Shell Programming and Scripting

Find first digit in string using expr index

I have looked for hours for an answer, so I have decided to request your guidance. I want to substract the first number (series of digits) contained in a string. This string is the output of another command. The substring (number) can be located at any position inside the string. I want to... (4 Replies)
Discussion started by: jcd
4 Replies

4. Shell Programming and Scripting

Single digit date to double digit date.

I have a var storing date var=`date` Now the date is returned as Mon Feb 2 00:25:48 PST 2009 Is there any way to check the date field alone ("2" in above case) and if its a single digit then add a prefix 0 to it and store the result in same variable "var" My intention in above case is... (3 Replies)
Discussion started by: villain41
3 Replies

5. UNIX for Dummies Questions & Answers

bash script to increment a digit in filename

Hi guys, Can someone help me out with this: I have a directory with files like the following, GHost++ 2010-03-14 04-01 DotaCash RD us_ca LC #7 (44m19s).w3g GHost++ 2010-03-14 04-06 DotaCash AP us_ca LC #8 (42m24s).w3g GHost++ 2010-03-14 04-07 DotaCash AR us_ca LC #10 (08m23s).w3g ... (4 Replies)
Discussion started by: hbjlee17
4 Replies

6. Shell Programming and Scripting

Creating 12 digit string value

Hi Masters, here is my req I have to create a 12 digit string which includes the user i/p Like if user input 2334 then the string will be 233411111111 ,if the user inputs 23345 then the string will be 233451111111 , So we dont know how many digits will the user inputs output will be 12... (16 Replies)
Discussion started by: Pratik4891
16 Replies

7. Shell Programming and Scripting

Check whether a string begin with uppercase, lowercase or digit!

Hi every body! I wrote script on Fedora (bash shell) to check whether a tring enter from user console is start with a uppercase/lowercase letter or a digit. But with this script i have some problem when I enter from character from 'b' to 'z' --> result is uppercase. This code look like ok but i... (9 Replies)
Discussion started by: nguyendu0102
9 Replies

8. Shell Programming and Scripting

awk length of digit and print at most right digit

Have columns with digits and strings like: input.txt 3840 3841 3842 Dav Thun Tax Cahn 146; Dav. 3855 3853 3861 3862 Dav Thun Tax 2780 Karl VI., 3873 3872 3872 Dav Thun Tax 3894 3893 3897 3899 Dav Thun Tax 403; Thun 282. 3958 3959 3960 Dav Thun Tax 3972 3972 3972 3975 Dav Thun Tax... (8 Replies)
Discussion started by: sdf
8 Replies

9. Shell Programming and Scripting

convert two digit in to single digit...

Hi Guys. My Input: ABCD 12 00 KL ABCD 12 08 DL ABCD 12 10 KK ABCD 12 04 LL ABCD 13 00 LP ABCD 13 1O LS Output: ABCD 12 0 KL ABCD 12 8 DL ABCD 12 10 KK ABCD 12 4 LL ABCD 13 0 LP (2 Replies)
Discussion started by: pareshkp
2 Replies

10. Shell Programming and Scripting

How to delete only the last digit in string

Hello, I would like to convert this string KBL3TEST1 into KBL3TEST How can i code this? Any help is appreciated regards, blashyou (6 Replies)
Discussion started by: blashyou
6 Replies

LEARN ABOUT PHP

dateinterval.format

DATEINTERVAL.FORMAT(3)							 1						    DATEINTERVAL.FORMAT(3)

DateInterval::format - Formats the interval

SYNOPSIS

       public string DateInterval::format (string  $format)

DESCRIPTION

	Formats the interval.

PARAMETERS

	      o $format
		-

	       The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
	      %).

	      +------------------+--------------------------------------+---+
	      |$format character |					|   |
	      | 		 |					|   |
	      | 		 |	       Description		|   |
	      | 		 |					|   |
	      | 		 |	      Example values		|   |
	      | 		 |					|   |
	      +------------------+--------------------------------------+---+
	      | 		 |					|   |
	      |        %	 |					|   |
	      | 		 |					|   |
	      | 		 |		Literal %		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		    %			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        Y	 |					|   |
	      | 		 |					|   |
	      | 		 | Years, numeric, at  least  2  digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		  01, 03		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        y	 |					|   |
	      | 		 |					|   |
	      | 		 |	      Years, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		   1, 3 		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        M	 |					|   |
	      | 		 |					|   |
	      | 		 | Months,  numeric,  at least 2 digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		01, 03, 12		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        m	 |					|   |
	      | 		 |					|   |
	      | 		 |	     Months, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		 1, 3, 12		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        D	 |					|   |
	      | 		 |					|   |
	      | 		 | Days, numeric,  at  least  2  digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		01, 03, 31		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        d	 |					|   |
	      | 		 |					|   |
	      | 		 |	      Days, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		 1, 3, 31		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        a	 |					|   |
	      | 		 |					|   |
	      | 		 | Total  number of days as a result of |   |
	      | 		 | a DateTime::diff or (unknown) other- |   |
	      | 		 | wise 				|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |	       4, 18, 8123		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        H	 |					|   |
	      | 		 |					|   |
	      | 		 | Hours,  numeric,  at  least 2 digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		01, 03, 23		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        h	 |					|   |
	      | 		 |					|   |
	      | 		 |	      Hours, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		 1, 3, 23		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        I	 |					|   |
	      | 		 |					|   |
	      | 		 | Minutes, numeric, at least 2  digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		01, 03, 59		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        i	 |					|   |
	      | 		 |					|   |
	      | 		 |	     Minutes, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		 1, 3, 59		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        S	 |					|   |
	      | 		 |					|   |
	      | 		 | Seconds,  numeric, at least 2 digits |   |
	      | 		 | with leading 0			|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		01, 03, 57		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        s	 |					|   |
	      | 		 |					|   |
	      | 		 |	     Seconds, numeric		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		 1, 3, 57		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        R	 |					|   |
	      | 		 |					|   |
	      | 		 | Sign " -" when negative, "  +"  when |   |
	      | 		 | positive				|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		   -, + 		|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      |        r	 |					|   |
	      | 		 |					|   |
	      | 		 | Sign  " -" when negative, empty when |   |
	      | 		 | positive				|   |
	      | 		 |					|   |
	      | 		 |					|   |
	      | 		 |		    -,			|   |
	      | 		 |					|   |
	      +------------------+--------------------------------------+---+
RETURN VALUES

	Returns the formatted interval.

NOTES

       Note

	       The DateInterval::format method does not recalculate carry over points in time strings nor  in  date  segments.	This  is  expected
	      because  it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
	      month and 1 day".

EXAMPLES

       Example #1

	      DateInterval example

	      <?php

	      $interval = new DateInterval('P2Y4DT6H8M');
	      echo $interval->format('%d days');

	      ?>

	      The above example will output:

	      4 days

       Example #2

	      DateInterval and carry over points

	      <?php

	      $interval = new DateInterval('P32D');
	      echo $interval->format('%d days');

	      ?>

	      The above example will output:

	      32 days

       Example #3

	      DateInterval and DateTime::diff with the %a and %d modifiers

	      <?php

	      $january = new DateTime('2010-01-01');
	      $february = new DateTime('2010-02-01');
	      $interval = $february->diff($january);

	      // %a will output the total number of days.
	      echo $interval->format('%a total days')."
";

	      // While %d will only output the number of days not already covered by the
	      // month.
	      echo $interval->format('%m month, %d days');

	      ?>

	      The above example will output:

	      31 total days
	      1 month, 0 days

SEE ALSO

       DateTime::diff.

PHP Documentation Group 												    DATEINTERVAL.FORMAT(3)
All times are GMT -4. The time now is 04:06 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy