I'm attempting to emulate another users .zshrc file. However, I'm sort of confused on what exactly the -g argument does for the typeset builtin. Here's what he has in his .zshrc file:
Note: I've figured out that typeset is now deprecated and is now replaced with the declare builtin.
Also I've tried something similar in another shell script, however the script returns with the following errors:
Output:
Any idea what the -g argument is for? And why is it giving me an error when I attempt to run the script (not the .zshrc file) in terminal?
Any idea what the -g argument is for? And why is it giving me an error when I attempt to run the script (not the .zshrc file) in terminal?
Moderator's Comments:
Please use CODE tags (rather than ICODE tags) when marking multi-line sample input, output, and code.
Last edited by Don Cragun; 07-16-2014 at 09:31 PM..
Reason: Add missing CODE tags and change ICODE tags to CODE tags.
Hi,
Can any one please explain me the use of 'typeset' in shell scripting?
I donot under stand the use and advantages of using typeset.
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623:454,585,664,773,888,345
......
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Hi Guys,
Happy New Year to you all!
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Hi,
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