I have a variable sumOfJEOutputFile which is the output file of an SQL command which contains the output of that SQL. The output looks like below:
I am using following code to manipulate the output:
Mail which I am getting has the subject as below:
I want to remove the space which is coming before 58 so that the subject looks like:
How can I achieve this?
i have a commad that display the total each directory size in KB.Below the commad and o/p:
ls -ltr | grep ^d | awk '{print $9}' | xargs du -sk
output:
what i want is the proper tab space b/w value and dir.? how to get that.
thanks in advance (10 Replies)
Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
Hi, I want to read lines from a file, and I'm using two methods
1 use
while read line
do
done<filename
2 use
line=`sed -n '3p' filename`
however, in both of them, I notice that the tab between fields are automatically converted to space
because I want to use awk over the... (10 Replies)
Hi,
I need help to remove tab delimited space in the $2 of a specific row. My file is like this:-
file1.txt
No_1 4 139 156
No_1 5 161 205
No_4 91 227 212
No_19 254 243 263
No_19 645 249 258
No_19 101 2492 2635
No_90 8 277 288... (5 Replies)
Hi,
I have a space delimited text file but I only want to change the first space to a tab and keep the rest of the spaces intact. How do I go about doing that? Thanks! (3 Replies)
Thank you for 4 looking this post.
We have a tab delimited file where we are facing problem in a lot of funny character. I have tried using awk but failed that is not working.
In the 5th field ID which is supposed to be a integer only of that file, we are getting corrupted data as below.
I... (12 Replies)
My file looks like
3 33 210.01.10.0 2.1 1211 560 26 45 1298 98763451112 15412323499 INPUT OK
3 233 40.01.10.0 2.1 1451 780 54 99 1876 78787878784 15423210199 CANCEL OK
Aim is to replace the spaces in each line by tab
Used: sed -e 's/ */\t/g'
But I get output like this... (3 Replies)
Discussion started by: sa@@
3 Replies
LEARN ABOUT MOJAVE
sql::translator::parser::dbix::class5.18
SQL::Translator::Parser::DBIx::Class(3) User Contributed Perl Documentation SQL::Translator::Parser::DBIx::Class(3)NAME
SQL::Translator::Parser::DBIx::Class - Create a SQL::Translator schema from a DBIx::Class::Schema instance
SYNOPSIS
## Via DBIx::Class
use MyApp::Schema;
my $schema = MyApp::Schema->connect("dbi:SQLite:something.db");
$schema->create_ddl_dir();
## or
$schema->deploy();
## Standalone
use MyApp::Schema;
use SQL::Translator;
my $schema = MyApp::Schema->connect;
my $trans = SQL::Translator->new (
parser => 'SQL::Translator::Parser::DBIx::Class',
parser_args => {
dbic_schema => $schema,
add_fk_index => 0,
sources => [qw/
Artist
CD
/],
},
producer => 'SQLite',
) or die SQL::Translator->error;
my $out = $trans->translate() or die $trans->error;
DESCRIPTION
This class requires SQL::Translator installed to work.
"SQL::Translator::Parser::DBIx::Class" reads a DBIx::Class schema, interrogates the columns, and stuffs it all in an $sqlt_schema object.
Its primary use is in deploying database layouts described as a set of DBIx::Class classes, to a database. To do this, see "deploy" in
DBIx::Class::Schema.
This can also be achieved by having DBIx::Class export the schema as a set of SQL files ready for import into your database, or passed to
other machines that need to have your application installed but don't have SQL::Translator installed. To do this see "create_ddl_dir" in
DBIx::Class::Schema.
PARSER OPTIONS
dbic_schema
The DBIx::Class schema (either an instance or a class name) to be parsed. This argument is in fact optional - instead one can supply it
later at translation time as an argument to "translate" in SQL::Translator. In other words both of the following invocations are valid and
will produce conceptually identical output:
my $yaml = SQL::Translator->new(
parser => 'SQL::Translator::Parser::DBIx::Class',
parser_args => {
dbic_schema => $schema,
},
producer => 'SQL::Translator::Producer::YAML',
)->translate;
my $yaml = SQL::Translator->new(
parser => 'SQL::Translator::Parser::DBIx::Class',
producer => 'SQL::Translator::Producer::YAML',
)->translate(data => $schema);
add_fk_index
Create an index for each foreign key. Enabled by default, as having indexed foreign key columns is normally the sensible thing to do.
sources
Arguments: @class_names
Limit the amount of parsed sources by supplying an explicit list of source names.
SEE ALSO
SQL::Translator, DBIx::Class::Schema
AUTHORS
See "CONTRIBUTORS" in DBIx::Class.
LICENSE
You may distribute this code under the same terms as Perl itself.
perl v5.18.2 2014-01-22 SQL::Translator::Parser::DBIx::Class(3)