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Full Discussion: Replace date in a file
Top Forums UNIX for Dummies Questions & Answers Replace date in a file Post 302906854 by Akshay Hegde on Tuesday 24th of June 2014 03:35:19 AM
Old 06-24-2014
Welcome to forums,

Try [untested]

Code:
$ sed "2s/=.*/=$(date +"%Y-%m-%d-%H.%M.%S" )/" file

Code:
$ awk 'FNR==2{sub(/=.*/,strftime("=%Y-%m-%d-%H.%M.%S",systime()))}1' file

 

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NetSDS::Util::DateTime(3pm)				User Contributed Perl Documentation			       NetSDS::Util::DateTime(3pm)

NAME
NetSDS::Util::DateTime - common date/time processing routines SYNOPSIS
use NetSDS::Util::DateTime; print "Current date: " . date_now(); DESCRIPTION
This package provides set of routines for date and time processing. EXPORTED FUNCTIONS
date_now_array([TIME]) Returns array of date items for given date. If source date is not set current date used. date_now([TIME]) Return [given] date as string. 2001-12-23 14:39:53 date_now_iso8601([TIME]) Return date as ISO 8601 string. 20011223T14:39:53Z <http://en.wikipedia.org/wiki/ISO_8601> http://www.w3.org/TR/NOTE-datetime <http://www.w3.org/TR/NOTE-datetime> date_strip(DATE) Trim miliseconds from date. date_date(DATE) Trim time part from date. date_time(DATE) Trim date part from date. time_from_string($string) Return parsed date/time structure. date_from_string($string) Return date from string representation. date_inc([INCREMENT, [TIME]]) Return date incremented with given number of seconds. date_inc_string([INCREMENT, [TIME]]) Return string representation of date incremented with given number of seconds. EXAMPLES
None yet BUGS
Unknown yet SEE ALSO
Date::Parse, Date::Format TODO
Import stuff from Wono project AUTHOR
Valentyn Solomko <val@pere.org.ua> Michael Bochkaryov <misha@rattler.kiev.ua> perl v5.12.4 2011-08-27 NetSDS::Util::DateTime(3pm)
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