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Top Forums UNIX for Dummies Questions & Answers To find and display the middle line in a file using single line command. Post 302906773 by in2nix4life on Monday 23rd of June 2014 11:45:18 AM
Old 06-23-2014
Code:
awk '{a[b++]=$0;}END{print a[int(b/2)];}' infile

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DXmSvnPositionDisplay(3X)												 DXmSvnPositionDisplay(3X)

NAME
DXmSvnPositionDisplay - Displays a specified entry. SYNOPSIS
int DXmSvnPositionDisplay( Widget widget, int entry, int position ); PARAMETERS
The identifier (widget ID) of the SVN widget. An integer that represents the number of the entry. The position of the entry, indicated by one of the following values: --------------------------------------------------------------- Value Description --------------------------------------------------------------- DXmSvnKpositionBottom The entry is positioned at the bottom of the display. DXmSvnKpositionTop The entry is positioned at the top of the display. DXmSvnKpositionMiddle The entry is positioned in the middle of the display. DXmSvnKpositionPreviousPage The entry is positioned on the page (display) of entries previ- ously displayed. DXmSvnKpositionNextPage The entry is positioned on the page (display) of entries to be displayed next. --------------------------------------------------------------- DESCRIPTION
The DXmSvnPositionDisplay routine ensures that the entries being displayed contain a specified entry. This routine allows the application to position a particular entry at the top, middle, or bottom of the display regardless of the number of entries being displayed. RETURN VALUES
An integer that returns as 1 (True). The routine returns a value of 0 (False) only when the specified position of the entry is SvnPosi- tionNextPage and the user is already at the bottom of the page (display). DXmSvnPositionDisplay(3X)
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