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Top Forums Shell Programming and Scripting Problem with occurence of square brackets Post 302905550 by Don Cragun on Thursday 12th of June 2014 06:02:40 AM
Old 06-12-2014
Quote:
Originally Posted by zaxxon
I decided to use neutronscott's solution, which I understand except the effect of these two expressions:

Code:
sed 's/[^[]*[[]\([^]]*\)]\([[][^]]*]\)*\([^]]*\)$/\1 -- \3/g' infile
            ^^^            ^^^

A group which consists of a single square bracket? I would have written the single square bracket without the enclosure but this does not work obviously.
If you understood the meaning of a repetition of a non-matching bracket expression (such as [^[]* which matches zero or more occurrences of any character except [), I'm surprised that you didn't understand the meaning of the matching bracket expression [[] which matches one occurrence of the [ character. Similarly, [^]] matches any character other than ] and []] matches a ].

You have to use the bracket expression [[] or escape the opening bracket \[ to distinguish it as a character to be matched (rather than the start of a bracket expression). In some contexts, you do not need to use a bracket expression or an escape to specify a closing bracket, but the meaning is is the same if you use []] and it is symmetric with the [[] if you have an editor that pairs up opening and closing parentheses, braces, and brackets.
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