Hi, Thanks for your code. When I am executing your code I am getting the below error. I do not know why? Coudl you please help...I appreciate your help in this regard. I am not a expert in UNIX shell.
Code:
awk: syntax error near line 5
awk: illegal statement near line 5
awk: bailing out near line 5
Last edited by Scrutinizer; 06-09-2014 at 07:30 AM..
Reason: code tags
Hello!
I have a textfile that look like this:
"83d1:46:2b";"20091008190000";"Rögle BK - Skellefteå";"Swedish"
"d4c:46:21";"20091008190000";"Södertälje - Brynäs";"Swedish"
"d4b:46:2";"20091008190000";"HV 71 - Färjestad";"Swedish"
"838:46:b";"20091010160000";"Skellefteå - HV 71";"Swedish"... (2 Replies)
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
Hi,
i have a flat file namely temp.txt with this data below
ID|name|contact_date
101|Kay|2013-12-26
102|let|2013-12-26
I need to modify the date data in the flat file into MM/DD/YYYY HH24:MI:SS format
let me know the code for this.
Thank you! (5 Replies)
Hi, I am extracting a date string from the source file like this :
06/05/2014 16:04:00
I want to change it to 05-JUN-14 04.05.00.000000000 PM
I basically store the date in a variable. I got solutions to change date in dd-mmm-yyyy format using tr but I guess it works only with the "date"... (8 Replies)
Hi,
We have csv file where date is coming in MM/DD/YYYY HH:MM:SS (06/23/2015 20:59:12) in multiple places
But we need to change the date format to DD/Mon/YYYY HH:MM:SS (23/Jul/2015 20:59:12) using shell script.
Please let us know how can we achieve the same. (16 Replies)
Hi All,
I'm new to forum good to hear all.
I stuck in converting date format in csv file using unix
csv file contains as below
,750,0000000000000000GCJR, ,06/22/2016 14:48:44
I want to convert into as below
,750,0000000000000000GCJR, ,06/22/2016 02:48:44 PM
Please reply asap..... (22 Replies)
Hi all,
I have a file as below,
i would like the change the format of the time from "11/7/2019 20:12" to "2019-07-11 20:12:00" in the last coloumn.
any awk solution on this.
Input:
2,0,695016,1961612,497212,5800804,0,0,161,33,7605,12226,23,10,66,0,0,34,11/7/2019 20:10... (4 Replies)
Discussion started by: Raghuram717
4 Replies
LEARN ABOUT CENTOS
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)
06-09-2014
