The command is
But it is not working when I replace "date" with my variable 'tdate'.
Is there a way in UNIX to get the date and timestamp from a stored variable?
BTW, You have unbalanced quotes in your original command. Highlighted in RED.
I have a file named "suspected" with series of line like these :
{'protocol': 17, 'service': 'BitTorrent KRPC', 'server': '219.78.120.166', 'client_port': 52044, 'client': '10.64.68.44', 'server_port': 8291, 'time': 1226506312L, 'serverhostname': ''}
{'protocol': 17, 'service': 'BitTorrent... (3 Replies)
Someone can help me write a script for change date fromat
from "Feb 4 18:44:03 2009" to 2009020418 ?
from "Mar 17 16:44:03 2009" to 2009031716 ? (4 Replies)
Can someone please tell me how to change the time and date format in the menu bar. I get to System Preferences -- Language and Text, format, customize, but I can't figure out what to do next. I want to change, say from Tue May 4 to 5 4 2010. How the heck do I do this? (5 Replies)
Hello,
I am trying to show today's date and time in a better format than ‘date' (Using positional parameters). I found a command mktime and am wondering if this is the best command to use or will this also show me the time elapse since 1/30/70? Any help would be greatly appreciated, Thanks... (3 Replies)
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
Hi,
I need help to convert the date format in .DAT file in unix.
I want to convert
10@@|SWIFT MT568 Extract@@|Apr 14 2014 5:47:52:563PM@@|Apr 14 2014 4:33:47:663PM@@||##|
into
10@@|SWIFT MT568 Extract@@|04/14/2014/ 5:47:52:563PM@@|04/14/2014 4:33:47:663PM@@||##|
Appreciate... (18 Replies)
Hi everybody!
I need to perform a task with a script but I have no idea how to do it, I hope someone could help me:
- on my linux pc I have many folders with movies, tv shows, toons, ecc.
They are shared by a dlna server to my panasonic tv where I can browse and see them.
The problem is that... (6 Replies)
Hi All,
I'm new to forum good to hear all.
I stuck in converting date format in csv file using unix
csv file contains as below
,750,0000000000000000GCJR, ,06/22/2016 14:48:44
I want to convert into as below
,750,0000000000000000GCJR, ,06/22/2016 02:48:44 PM
Please reply asap..... (22 Replies)
Discussion started by: Raghureds
22 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)