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Full Discussion: Help with Bash quoting
Top Forums Shell Programming and Scripting Help with Bash quoting Post 302904781 by Corona688 on Friday 6th of June 2014 11:19:37 AM
Old 06-06-2014
The single or double quoting is not the problem, you seem to have a handle on it.

The problem is that the shell's not going to convert date -d ... into a string unless you ask it to.

Code:
echo "so we want sudo access to expire on $(date -d "$num_days days")"

The $( ) syntax will do so nicely. It even nests inside other "" quite unlike the old ` ` syntax.
 

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PX_DATE2STRING(3)														 PX_DATE2STRING(3)

px_date2string - Converts a date into a string.

SYNOPSIS
string px_date2string (resource $pxdoc, int $value, string $format) DESCRIPTION
Turns a date as it stored in the paradox file into human readable format. Paradox dates are the number of days since 1.1.0000. This func- tion is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the example below. PARAMETERS
o $pxdoc - Resource identifier of the paradox database as returned by px_new(3). o $value - Value as stored in paradox database field of type PX_FIELD_DATE. o $format - String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by date(3) (Y, y, m, n, d, j, L). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 Turn a paradox date into a human readable form <?php $px = px_new(); /* make up a date as it could be stored in */ /* a date field of a paradox db. */ /* 700000 days since 1.1.0000. */ $days = 700000; /* Use the calendar functions to print a */ /* human readable format of the date */ echo jdtogregorian($days+1721425)." "; /* px_date2string() outputs the same */ echo px_date2string($px, $days, "n/d/Y")." "; px_delete($px); ?> The above example will output: 7/15/1917 7/15/1917 SEE ALSO
px_timestamp2string(3), jdtogregorian(3). PHP Documentation Group PX_DATE2STRING(3)
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