Hi,
I'm trying following:echo "test line XA24433 test" | sed 's/.*X\(.*\)/X\1/'
XA24433 test While I want the output as: XA24433
I want to grab the words starting with letter X till the next space, this word can be anywhere in the line. (9 Replies)
Hi!
I'm trying to write a regexp but I have no luck...
I have a string like this:
param1=sometext¶m2=hello¶m3=bye
Also, the string can be simply:
param2=hello
I want to return the value of param2: "hello".
How can I do this?
Thanks. (3 Replies)
Hello,
I would like to replace Line 187 of my file named run_example.
The original line is below, including the spaces:
celldm(1) = 6.00,
I want it to become something like
celldm(1) = 6.05,
or
celldm(1) = 6.10,
where the number is stored in a variable called... (6 Replies)
Hi
I need to get text that are within ""
For example
File:
asdasd "test test2" sadasds asdda asdasd "demo demo2"
Output:
test test2 demo demo2
Any help is good
Thank you (12 Replies)
please consider this:
echo "11111*X*005010X279~ST*270*1111111*005010X279~BHT*0011*11" | sed 's/.*\(005010X(\d)(\d)(\d)*\).*$/\1/'i'm searching for first occurrence of 005010X while leaving rest of characters out.
:confused:
any tips? thnx in advance guys. (7 Replies)
Hi ,
I am learing sed
echo abc 123 def 456 | sed 's|\(*\) \(*\)|\1|'
is returning abc def 456
i was hoping abc def "\1" should only print the occurence of the first pattern
but according to my understanding it is just removing the first occurence of the second pattern... (7 Replies)
Hi all,
I want to get a substring from a string based on given delimiter, for example:
str="foo|bar|baz" with delimiter "|",
I want to get one substring at each time with the order number the substring in the whole string,
given 1 to get "foo",
given 2 to get "bar",
given 3 to get "baz",
I... (2 Replies)
Hello All,
I'm trying to extract the lines between two consecutive elements of an array from a file.
My array looks like:
problem_arr=(PRS111 PRS213 PRS234)
j=0
while } ]
do
k=`expr $j + 1`
sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt
---some operation goes... (11 Replies)
Hi , I need to remove pipe character from a |^ delimeted file.
Something like |^tran|sformers||^|revenge |of fallen|^ to
|^transformers|^revenge of fallen|^...
Cold anybody please help to build the regular expression using sed .
many thanks.
Please use code tags next time for... (1 Reply)
Discussion started by: kokjek
1 Replies
LEARN ABOUT DEBIAN
regexp
Regexp(3I) InterViews Reference Manual Regexp(3I)NAME
Regexp - regular expression searching
SYNOPSIS
#include <InterViews/regexp.h>
DESCRIPTION
A Regexp encapsulates a regular expression pattern and defines operations for searching and matching the pattern against a string. The
syntax of the regular expression pattern is the same as that for ed(1). Information can be obtained about the most recent match of the
regular expression (and its sub-expressions).
PUBLIC OPERATIONS
Regexp(const char* pattern)
Regexp(const char* pattern, int length)
Construct a new Regexp for pattern.
int Match(const char* text, int length, int index)
Attempt a match against text (of length length) at position index. The return value is the length of the matching string, or a neg-
ative number if the match failed.
int Search(const char* text, int length, int index, int range)
Search for a match in the string text (of length length). Matches are attempted starting at positions between index and index plus
range. If range is positive the first match after index is reported. If range is negative the first match before index is
reported. The return value is the index of the starting position of the match, or a negative number if there is no match in the
specified range.
int BeginningOfMatch(int subexp)
int EndOfMatch(int subexp)
Return information about the most recent match. If subexp is zero (the default), information is reported for the complete regular
expression. Other values of subexp refer to sub-expressions in the pattern. For example, if subexp is 2, information is returned
for the sub-expression specified by the second pair of ( and ) delimiters in the pattern.
SEE ALSO ed(1)InterViews 23 May 1989 Regexp(3I)