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Top Forums Shell Programming and Scripting Sed: printing lines AFTER pattern matching EXCLUDING the line containing the pattern Post 302904488 by Scrutinizer on Wednesday 4th of June 2014 09:30:17 AM
Old 06-04-2014
Try:
Code:
sed -n '/pattern/,${/pattern/!p;}' file

(but this will delete all lines with /pattern/ from the output)

Code:
sed '1,/pattern/d' file

But this will give the wrong result if the pattern is on line 1

GNU sed:
Code:
sed '0,/pattern/d' file


--
Using awk:
Code:
awk 'p; /pattern/{p=1}' file



---
On Solaris use /usr/xpg4/bin/awk rather than awk

Last edited by Scrutinizer; 06-05-2014 at 06:09 AM..
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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