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Full Discussion: Looping through the contents of array for output name
Top Forums UNIX for Dummies Questions & Answers Looping through the contents of array for output name Post 302904225 by SriniShoo on Tuesday 3rd of June 2014 03:02:47 AM
Old 06-03-2014
Code:
awk -v fname='japan usa uk' 'BEGIN {split(fname, a)}
  {for(i = 1; i <= NF; i++)
    {print $i > ("201005" a[i] ".txt")}}' alldata.dat

This User Gave Thanks to SriniShoo For This Post:
ida1215
 

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LEARN ABOUT DEBIAN

zip_name_locate

ZIP_NAME_LOCATE(3)					     Library Functions Manual						ZIP_NAME_LOCATE(3)

NAME

       zip_name_locate - get index of file by name

LIBRARY

       libzip (-lzip)

SYNOPSIS

       #include <zip.h>

       int zip_name_locate(struct zip *archive, const char *fname, int flags);

DESCRIPTION

       The  zip_name_locate  function returns the index of the file named fname in archive.  If archive does not contain a file with that name, -1
       is returned.  The are specified by or'ing the following values, or 0 for none of them.

	      ZIP_FL_NOCASE  Ignore case distinctions.

	      ZIP_FL_NODIR   Ignore directory part of file name in archive.

RETURN VALUES

       zip_name_locate returns the index of the file named fname or -1, if archive does not contain an entry of that name.

ERRORS

       The zip_name_locate function fails and sets the error information to ZIP_ER_NOENT if no entry of the name fname is found  in  the  archive.
       If one of the arguments is invalid, the error information is set to ZIP_ER_INVAL.

SEE ALSO

       libzip(3), zip_get_name(3)

AUTHORS

       Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at>

NiH								  October 4, 2006						ZIP_NAME_LOCATE(3)
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