Did you try the code or just consider it to look wrong...? Why?
The whole point of using a union, and the whole point of adding type to the beginning of your CS and DS structures, was that they'd all have the same memory layout.
The compiler warns you since it doesn't know you built with these assumptions in mind. You can avoid the warning with a typecast if you want:
May i know how to pass an argument to a function in a shell script?
Sorry, i din stated that it is in a shell script in my previous post.
Means: checkStatus() {
...........
}
read status;
I wanna use the status in the function checkstatus, how... (2 Replies)
I need to pass a parameter to a function in a script. My parameter is a string. When I display the parameter within my function, I only get the first word from string I pass in.
How can I make the function receive the whole string (and not terminate at the first space it encounters)?.
part of... (1 Reply)
I need to pass a parameter to a function in a script. My parameter is a string. When I display the parameter within my function, I only get the first word from string I pass in.
How can I make the function receive the whole string (and not terminate at the first space it encounters)?.
part of... (2 Replies)
Hello all
im trying to build function that will return void function pointer
what is mean is ( not working )
the main function
void * myClass::getFunction(int type){
if(type==1)
return &myClass::Test1;
if(type==2)
return &myClass::Test2;
}
void myClass::Test1(){... (1 Reply)
Hi All,
Calling a function with one argument and storing the return value in a shell script is as below:( so far I know)
value="`fun_1 "argument1"`"
Its working perfectly for me.
Can u help me with passing more than one argument and storing the return value
Thnaks in advance
JS (1 Reply)
Hi,
I have 2 ksh scripts.
Script1.ksh contains function definition.
script1.ksh
function f1() {
while getopts a:c: args
do
case $args in
a) ARG1=$OPTARG ;;
c) ARG2=$OPTARG ;;
\?) echo "Error no valid Arguments passed"
esac
done
echo $ARG1
echo $ARG2
script2.sh (2 Replies)
Hi,
I have a function which connects to the db and runs the sql.
it works fine when I run it like: function "select empname from emp;"
but when I try to pass the sql string to a variable which in turn in fed to the function , it throws error.
please advise.
Thanks,
Arnie. (1 Reply)
Hi all,
In the given script code .
I want to pass the maximum value that variable "i" will have in function DivideJobs () to variable $max of function SubmitCondorJob().
Any help?
Thanks
#!/bin/bash ... (55 Replies)
i am passing input parameter 'one_two' to the script , the script output should display the result as below
one_1two
one_2two
one_3two
if
then
echo " Usage : <$0> <DATABASE> "
exit 0
else
for DB in 1 2 3
do
DBname=`$DATABASE | awk -F "_" '{print $1_${DB}_$2}`
done
fi (5 Replies)
Hi All,
Just trying to implement the below shell script using AIX ksh shell.
myfunc {
eval "$*"
}
CMD='ls -la /etc/hosts | awk '{print $9"|"$5}''
myfunc $CMD
Keeping getting "|}: not found" errors, any pointers would greatly be appreciated.
Kind Regards
Ed
Please... (2 Replies)
Discussion started by: eo29
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)