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Top Forums Shell Programming and Scripting Not getting array in .awk file and print it Post 302902932 by nes on Friday 23rd of May 2014 01:07:17 AM
Old 05-23-2014
When I tried to print that values in test.sh file, I am getting 2 values from array

Code:
set -A IDARR $ID
echo "${IDARR[*]}"
echo | awk -f test.awk -v TempArr="${IDARR[*]}"

Getting out put as below :
3 1

Thanks in advance... Smilie
 

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FORWARD_STATIC_CALL(3)							 1						    FORWARD_STATIC_CALL(3)

forward_static_call - Call a static method

SYNOPSIS
mixed forward_static_call (callable $function, [mixed $parameter], [mixed $...]) DESCRIPTION
Calls a user defined function or method given by the $function parameter, with the following arguments. This function must be called within a method context, it can't be used outside a class. It uses the late static binding. PARAMETERS
o $function - The function or method to be called. This parameter may be an array, with the name of the class, and the method, or a string, with a function name. o $parameter - Zero or more parameters to be passed to the function. RETURN VALUES
Returns the function result, or FALSE on error. EXAMPLES
Example #1 forward_static_call(3) example <?php class A { const NAME = 'A'; public static function test() { $args = func_get_args(); echo static::NAME, " ".join(',', $args)." "; } } class B extends A { const NAME = 'B'; public static function test() { echo self::NAME, " "; forward_static_call(array('A', 'test'), 'more', 'args'); forward_static_call( 'test', 'other', 'args'); } } B::test('foo'); function test() { $args = func_get_args(); echo "C ".join(',', $args)." "; } ?> The above example will output: B B more,args C other,args SEE ALSO
forward_static_call_array(3), call_user_func_array(3), call_user_func(3), is_callable(3), information about the callback type. PHP Documentation Group FORWARD_STATIC_CALL(3)
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