Find week of the year for given date using date command inside awk Post: 302902343

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LEARN ABOUT PHP

cal_from_jd

CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS

       array cal_from_jd (int  $jd, int  $calendar)

DESCRIPTION

       cal_from_jd(3)  converts  the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
       CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.

PARAMETERS

	      o $jd
		- Julian day as integer

	      o $calendar
		- Calendar to convert to

RETURN VALUES

	Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and	month  and
       the date in string form "month/day/year".

EXAMPLES

       Example #1

	      cal_from_jd(3) example

	      <?php
	      $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
	      print_r(cal_from_jd($today, CAL_GREGORIAN));
	      ?>

	      The above example will output:

	      Array
	      (
		  [date] => 8/16/2003
		  [month] => 8
		  [day] => 16
		  [year] => 2003
		  [dow] => 6
		  [abbrevdayname] => Sat
		  [dayname] => Saturday
		  [abbrevmonth] => Aug
		  [monthname] => August
	      )

SEE ALSO

       cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).

PHP Documentation Group 													    CAL_FROM_JD(3)