If I did indeed grep something out of it, why woudln't $result show nothing?
When I do $? , it does show success...
What is the proper syntax so that $result shows actual thing it's grepping out?
result=`(ssh $host tail -1 /something/somethingelse) | egrep -i "value" >dev/null`
#echo... (3 Replies)
Hi,
have a basic query.
Please see the below code:
list="one two three"
for var in $list ; do
echo $var
list="nolist"
Done
Wht if I want to print only first/ last line in the list
Eg one & three
Regards
er_ashu (3 Replies)
I have a script problem that I am not able to solve due my very limited understanding of unix/awk.
This is the contents of test.sh
awk '{print $1}'
From the prompt if I enter:
./test.sh Hello World
I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
sorry for being dumb here, but is there a way my for loop can take an entire line of a file into consideration instead of each word in a line... ill explain
if i have a file like this
# cat list
serial: 23124
hostname: server1
and a script that does this
# cat list.sh
#!/bin/sh
... (6 Replies)
I'm trying to approach a problem but all I'm coming up with are complex ways to manipulate the data. But still not getting the desired outcome.
directory of files....
file-100-foo
file-100-man
file-100-chu
Need to copy the files and increment the number in the file name
... (4 Replies)
Hi,
I have a text file with data in that I wish to extract, assign to a variable and process through a loop.
Kind of the process that I am after:
1: Grep the text file for the values.
Currently using:
cat /root/test.txt | grep TESTING= | awk -F"=" '{ a = $2 } {print a}' | sort -u
... (0 Replies)
Hi,
I have a loop like this -
while read item
do
// fire insert query
done < itemList.txt
The itemList.txt has say, 1000 records. Now what I do is that rhough another program, I make the itemList.txt EMPTY, but still the INSERT query keeps firing the sequence of records.
... (18 Replies)
hey guys
I would really appreciate some help, i need to do a project for a job that requires minimal UNIX scripting and im REALLY stuck
basically Im stuck at what i believe is something really simple but i just dont have a clue how to do it efficiently and properly and i REALLY appreciate some... (16 Replies)
Hello all! I am very new to shell and Linux in general (I just started 2 days ago), I am trying to write a script that adds the size of the directories and files in a given directory and displays messages if the user puts in something wrong. I think I have covered all the possible problems except... (3 Replies)
I have two shell scripts in the different directories listed below,
/root/dev/dir1/test.sh
/root/dev/dir2/master.sh
I am executing the master.sh script from the test.sh like below and getting 'Permission denied' error.
#! /bin/sh
#test.sh
path='/root/dev'
$path/dir2/master.sh
But it... (2 Replies)
Discussion started by: vel4ever
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)