Hi,
I am having a file which contains records as follows:
DETAIL_KEY~12344|ACTIVE_PASSIVE~Y|AVG_SIZE_OF_RESPONSE~123123131
DETAIL_KEY~12344|ACTIVE_PASSIVE~Y|AVG_SIZE_OF_RESPONSE~123123131
DETAIL_KEY~12344|ACTIVE_PASSIVE~Y|AVG_SIZE_OF_RESPONSE~123123131... (4 Replies)
hi
i have a file with these strings:
123_abc_X1116990
how to get rid of 123_abc_ and keep only X1116990?
I have columns of these:
123_abc_X1134640
123_dfg_X1100237
123_tyu_X1103112
123_tyui_X1116990
thx (5 Replies)
Here is my problem.
I have a list of phone numbers that I want to use only the last 4 digits as PINs for something I am working on. I have all the numbers in a file but now I want to be removed all items EXCEPT the last 4 digits.
I have seen sed commands and some grep commands but I am... (10 Replies)
Hi please help in writing a script for replacing all the non-iso8859-1 characters to question marks.
I need a pattern of this kind
"sed s/<non-iso char range>/?/g < ipfile > opfile"
Please help me in this. (2 Replies)
I have a file with all kinds of ^M at the end of each line. How the heck can these be removed? I tried a global search and replace, but it doesn't seem to work.
Thanks! (8 Replies)
Hi,
I have a file with lines like below.
I need to remove first few characters from each line until a date format is found.
05/06/12 20:47:02 GUMGUY@98.192.174.74{42B42A72AC955F5926621273E3A15059.tomcat2}TP-Processor15 LogExchUsage: ERROR:
05/06/12 20:47:02... (8 Replies)
Hi Gurus,
when I run following command to split one line file to multiple lines, it stopped because of hitting un-printable special charactor.
awk -v L="$2" '{for (i=1; i<=length($0); i+=L) print substr($0, i, L)}' "$1" > "$1"_split
I use cat -A, I can see one un-printable charactor M-^T.
how... (1 Reply)
I have been having an encoding problem that I need to solve.
I have an 4-column tab-separated file: I need to remove all of the lines that contain the string 'vis-à-vis'
achiever-n vis-à-vis+ns-j+vp oppose-v 1
achiever-n vis-à-vis+ns-the+vg assess-v 1
administrator-n ... (4 Replies)
here's what im trying to do.
i have a file containing lines similar to this:
data.txt:
1hsRmRsbHRiSFZNTTA1dlEyMWFkbU5wUW5CSlIyeDFTVU5SYjJOSFRuWmpia0ZuWXpKV2FHTnRU
1lKUnpWMldrZFZaMG95V25oYQpSelEyWTBka2QyRklhSHBrUjA1b1kwUkJkd3BOVXpWM1lVaG5k... (5 Replies)
Discussion started by: SkySmart
5 Replies
LEARN ABOUT OSX
svk::log::filter::grep
SVK::Log::Filter::Grep(3) User Contributed Perl Documentation SVK::Log::Filter::Grep(3)SYNOPSIS
SVK::Log::Filter::Grep - search log messages for a given pattern
DESCRIPTION
The Grep filter requires a single Perl pattern (regular expression) as its argument. The pattern is then applied to the svn:log property
of each revision it receives. If the pattern matches, the revision is allowed to continue down the pipeline. If the pattern fails to
match, the pipeline immediately skips to the next revision.
The pattern is applied with the /i modifier (case insensitivity). If you want case-sensitivity or other modifications to the behavior of
your pattern, you must use the "(?imsx-imsx)" extended pattern (see "perldoc perlre" for details). For example, to search for log messages
that match exactly the characters "foo" you might use
svk log --filter "grep (?-i)foo"
However, to search for "foo" without regards for case, one might try
svk log --filter "grep foo"
The result of any capturing parentheses inside the pattern are not available. If demand dictates, the Grep filter could be modified to
place the captured value somewhere in the stash for other filters to access.
If the pattern contains a pipe character ('|'), it must be escaped by preceding it with a '' character. Otherwise, the portion of the
pattern after the pipe character is interpreted as the name of a log filter.
STASH /PROPERTY MODIFICATIONS
Grep leaves all properties and the stash intact.
perl v5.10.0 2008-08-04 SVK::Log::Filter::Grep(3)