Problem exists when MonthID=201307 and i run the above script and it returns 20136 instead of 201306
Help is appreciated to get the MonthID in correct format.
Moderator's Comments:
Please use ICODE tags, not QUOTE tags, when displaying in-line code, input, and output samples.
Hi pinnacle,
I find this very confusing.
You haven't said what shell or operating system you're using, but from the [[ expression ]], I assume that you're not using a Bourne shell and that you are probably using bash or ksh.
But, your code sample doesn't define MonthID (or monthid). And the way you define MonthID in the description of what you're trying to do (with spaces around the equals sign in MonthID = 201301 won't work with any shell that I know of that supports [[ ... ]].
If my assumptions are correct:
You are using a Korn shell, a bash shell, or another shell that recognizes POSIX arithmetic expansions, and
you want to work with a variable named MonthID, not monthid,
then the following should do what you want MUCH more efficiently:
Code:
MonthID=${1:-201301}
printf 'Starting MonthID: %d\n' "$MonthID"
MonthID=$((MonthID - 1))
if [ $((MonthID % 100)) -eq 0 ]
then MonthID=$((MonthID - 88))
fi
printf "Ending MonthID: %d\n" "$MonthID"
In fact, with a bash or ksh shell, it can be simplified further to:
Code:
MonthID=${1:-201301}
printf 'Starting MonthID: %d\n' "$MonthID"
if [ $((--MonthID % 100)) -eq 0 ]
then ((MonthID -= 88))
fi
printf "Ending MonthID: %d\n" "$MonthID"
Quote:
Originally Posted by Aia
substitute echo for printf
Code:
printf "%d%02d\n" $c, $b
Hi Aia,
There is no need for the comma in $c,, and with some shells having a comma there will generate a syntax error.
These 2 Users Gave Thanks to Don Cragun For This Post:
#!/bin/ksh
month=`date | cut -c5-8`
year=`date | cut -c24-28`
echo "$month"
echo "$year"
--- This gives me output as Feb and 2009
but now I want to substract the 1 month from the current script and want output as
Jan 2009.
Please note I have searched a lot on forum and found... (5 Replies)
We have a list of files (raw and jpeg types) with 2 different extensions (rw2 and jpg).
When there is both the raw and jpeg files, their file numbers must be the same (215 and 215, 218 and 218).
Sometimes there is only the jpeg file (216,217).
bla_215.rw2
bla_215.jpg
bla_216.jpg
bla_217.jpg... (9 Replies)
Please guide if you know how to solve this.
I have a tab delimited INPUT FILE where each record is separated by -----
-----
ABC 4935402 4936680 Pattern=Cheers07080.1
ABC 4932216 4932368 Pattern=Cheers07080.1
ABC 4931932 4932122 ... (8 Replies)
I've start and end time in two columns. How can I substract time from column 2 and column 1 and receive output in another file 'd' ?
$ cat c
12:55:04 2:03:56
2:03:56 3:20:17
14:00:00 13:05:00 (1 Reply)
Hi everyone,
I have a file containing one column and I want to subtract the first value (value of first line) from each line's value.
79304
99299
119294
139289
159284
179279
199274
219269
239264
259259
279254
299249
319244
339239
359234I tried working on an awk solution with... (1 Reply)
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Hello,
i`m looking for some way to add to some date an partial number of months, for example to 2015y 02m 27d + 2,54m
i need to write this script in php or bash or sh or mysql or perl in normal time o unix time
i`m asking or there are any simple way to add partial number of month to some... (14 Replies)
Hi,
I need all file names in a folder which has date >= 10th of last month,
Example
: files in folder
AUTO_F1_20140610.TXT
BUTO_F1_20140616.TXT
CUTO_F1_20140603.TXT
FA_AUTO_06012014.TXT
LA_AUTO_06112014.TXT
MA_AUTO_06212014.TXT
ZA_AUTO_06232014.TXT
Output:
AUTO_F1_20140610.TXT... (9 Replies)
05-07-2014
