Hi all,
I have an xml file which have several sections as the following:
<process-type id="NIR" module-id="OC4J">
<module-data>
<category id="start-parameters">
<data id="java-options" value="-server... (4 Replies)
I have a file name called fruits.
In this file the prices keep on changing & the order in which fruits are listed keep on changing.
$ cat fruits
fruitname price/pound
redapples 30
grapes 50
oranges 20
$echo $custom_price
35
What I want to do is that if the file "fruits" contains... (1 Reply)
Hi guys,
with sed when I need to make a substitution inside a line containing a specific keyword, I usually use:
sed '/keyword/ s/cat/dog/g'
This will substitute "cat" with "dog" on those lines containing "keyword". Now I want to use this inside vi, for several reason that I cannot... (2 Replies)
Suppose,
d=ABC*.BGH.LKJ
Now I want to replace 'DEFGHIJ' instead of '*.B' and store the value in d. Any Idea? Can we use sed here?
The outout should be like this:
d=ABCDEFGHIJGH.LKJ
Please help.. (4 Replies)
Hi,
I have a string like this user can specify different query sets that is why "or" is mentioned:
$string="](";
or
$string="]((";
or
$string="](((";
or
$string="]((((("; (1 Reply)
Hi,
I started exploring unix recently. Now i have got a requirement like i have a input file where i am having some strings line by line (One string Might be single line or multiple lines). Now i need find these strings in another file and if its found i have to replace it with another string... (2 Replies)
Objective is to substitute Jan with 01, Feb with 02 and so on. The month will be provided as input.
I could construct below awk and it worked.
echo Jun | \
awk 'BEGIN{split("Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec",mon," ")}{ for (i=1;i<=12;i++){ if ($1==mon) printf("%02d\n",i)} }'
... (4 Replies)
I have to parse ASCII files, output the relevant data to a comma-delimited file and load it into a database table.
The specs for the file format have been recently updated and one section is causing problems. This is the original layout for that section.
... (2 Replies)
Dear all,
I try to replace a string of characters in a file (MyFile.txt) by a multiline value of the variable "Myvar":
$ cat MyFile.txt
DESCRIPTION '@TargetTable SCHEMA'
(
@InputFlowDef
);
$
The content of Myvar:
$ echo "$Myvar"
col1
, col2
, col3
$ (4 Replies)
HI
I am trying to use the following code in the shell script (using grep)
usage()
{
echo "Usage: ./$0 <file name> <interval> <pattern>"
}
METRICS_FILE=$1
INTERVAL=$2
PATTERN="$3"
..
if
then
PATTERN="grep Gx"
fi
COUNT=`cat ${METRICS_FILE} | "${PATTERN}" |egrep... (8 Replies)
Discussion started by: asifansari
8 Replies
LEARN ABOUT LINUX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD