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Operating Systems HP-UX Replacing Hex Characters In A File Using awk? Post 302899283 by AndyBSG on Monday 28th of April 2014 10:27:50 AM
Old 04-28-2014
Question Replacing Hex Characters In A File Using awk?

Hi guys,

First off, i'm a complete noob to UNIX and LINUX so apologies if I don't understand the basics!

I have a file which contains a hex value of '0D' at the end of each line when I look at it in a hex viewer.

I need to change it so it contains a hex value of '0D0A0A'

I thought the easiest way would be using awk so I tried this

Code:
awk '{sub("\x0D","\x0D\x0A\x0A")}' filename

It doesn't give me an error but neither does it seem to work. Can anyone tell me what i'm doing wrong?

Thanks for any advice!

Last edited by AndyBSG; 04-28-2014 at 11:46 AM..
 

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HEXBRAILLE(1)						      General Commands Manual						     HEXBRAILLE(1)

NAME
hexbraille - Algorithmically generate the Unicode Braille range (U+28xx) SYNOPSIS
hexbraille > output_font.hex DESCRIPTION
hexbraille generates a GNU Unifont .hex format file (written on stdout) containing the Braille dot patterns in the Unicode range U+2800..U+28FF. FILES
braille.hex output font files SEE ALSO
bdfimplode(1), hex2bdf(1), hex2bdf-split(1), hex2sfd(1), hexdraw(1), hexmerge(1), johab2ucs2(1), unibmp2hex(1), unicoverage(1), unidup(1), unihex2bmp(1), unipagecount(1), uniunmask(1) AUTHOR
hexbraille was written by Roman Czyborra, who named this script "braille.pl". In 2003, Roman incorporated a bug fix from Dominique at unruh.de. LICENSE
hexbraille is Copyright (C) 1998 Roman Czyborra, and is released under the following terms (taken from http://czyborra.com): "All of my works you find here are freeware. You may freely copy, use, quote, modify or redistribute them as long as you properly attribute my contribution and have given a quick thought about whether Roman might perhaps be interested to read what you did with his stuff. Hori- zontal rules don't apply." BUGS
No known bugs exist. 2008 Jul 06 HEXBRAILLE(1)
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