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Top Forums UNIX for Dummies Questions & Answers Produce the number 2014 without any numbers in your source code... Post 302899207 by Don Cragun on Monday 28th of April 2014 05:13:31 AM
Old 04-28-2014
Quote:
Originally Posted by SriniShoo
Code:
 
awk 'BEGIN{a++;printf "%d%d%d%d\n",++a,c++,c++,a+c}'

Although this will work on many (probably most) systems, the standards don't specify the order in which arguments to functions are evaluated. In addition to printing 2014 (with a left to right evaluation), it could also print 2101 (with a right to left evaluation), and several other values with less likely evaluation orders.
This User Gave Thanks to Don Cragun For This Post:
 

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OPERATOR(7)                                                  Linux Programmer's Manual                                                 OPERATOR(7)

NAME
operator - C operator precedence and order of evaluation DESCRIPTION
This manual page lists C operators and their precedence in evaluation. Operator Associativity () [] -> . left to right ! ~ ++ -- + - (type) * & sizeof right to left * / % left to right + - left to right << >> left to right < <= > >= left to right == != left to right & left to right ^ left to right | left to right && left to right || left to right ?: right to left = += -= *= /= %= <<= >>= &= ^= |= right to left , left to right COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the latest version of this page, can be found at https://www.kernel.org/doc/man-pages/. Linux 2011-09-09 OPERATOR(7)
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