I don't think that the date command is intended for that. I can sort-of get it to work by abusing the timezone concept. Note that I had to switch signs.
Hi Friends :)
I have a long file having fields in the form :
Field1 yy/mm/dd hh:mm:ss Duration(Sec)
line 1) 123123 05/11/30 12:12:56 145
line 2) 145235 05/11/30 12:15:15 30
line 3) 145264 05/11/30 13:14:56 178
.
.
I want to subtract yy/dd/dd hh:mm:ss in line (2) from yy/mm/dd hh:mm:ss in... (1 Reply)
Hello,
Im writing a script using the ksh shell. I have 2 variables in the script:
CURRTIME
PREVTIME
Example, if CURRTIME=13:00, I want to somehow calculate what the time was an hour ago so that PREVTIME=12:00
Right now I have the following:
CURRTIME=`date +%H:%M`
How can I... (4 Replies)
i have the time 20100421043335 in format (date +%Y%m%d%H%M%S),and i want to be able to get the previous time 2 minutes ago,which is
20100421043135 (9 Replies)
need some help on the below requirement:
File1:
SV,22,20100501140000,JFK,RUH
SV,29,20100501073000,BOM,RUH
SV,29,20100501073000,SIN,RUH
third filed is datetime which is of the format (yyyymmddhh24miss)
File2
JFK,+,0500
BLR,-,0530
SIN,-,0800
for every line of file 1, take 4... (9 Replies)
Hi,
Need to subtract 5 seconds after syncing my Linux server from NTP like;
#ntpdate time.myorg.int.
This script will only run once in each morning at 9 AM.
Please help me. (4 Replies)
Hello All ,
Please support for below request
how to change format and subtract time and date and get average.
xxx 13-OCT-15 11.32.18.241000 AM 13-OCT-15 11.35.49.089080 AM
xxx 13-OCT-15 11.32.24.000000 AM 13-OCT-15 11.45.17.810904 AM
xxx 13-OCT-15 11.32.25.232000 AM ... (1 Reply)
INPUT:
16:45:51 10051 77845
16:45:51 10051 77845
16:46:52 10051 77846
16:46:53 10051 77846
Match the last PID then subtract second line time with first line.
Please help me with any command or script. (3 Replies)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
date_parse_from_format
DATE_PARSE_FROM_FORMAT(3) 1 DATE_PARSE_FROM_FORMAT(3)date_parse_from_format - Get info about given date formatted according to the specified formatSYNOPSIS
array date_parse_from_format (string $format, string $date)
DESCRIPTION
Returns associative array with detailed info about given date.
PARAMETERS
o $format
- Format accepted by DateTime.createFromFormat(3).
o $date
- String representing the date.
RETURN VALUES
Returns associative array with detailed info about given date.
EXAMPLES
Example #1
date_parse_from_format(3) example
<?php
$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));
?>
The above example will output:
Array
(
[year] => 2009
[month] => 1
[day] => 6
[hour] => 13
[minute] => 0
[second] => 0
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 0
[errors] => Array
(
)
[is_localtime] => 1
[zone_type] => 1
[zone] => -60
[is_dst] =>
)
SEE ALSO DateTime.createFromFormat(3), checkdate(3).
PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)