This question has been asked many times, but my problem is slightly different.
In my shell script i am connecting to oracle database and loading the results to .dat file. This .dat file is later used to create to .xls file[to be sent to the users] Some times the size of .dat file becomes more than 120000 bytes. In these cases, the sed and other commands used in the script fails with cannot execute [Argument list too long] error.
I tried splitting the .dat file to smaller files, but i am not even able to split the file and it again throws me the same [Argument list too long] error.
The problem is not just with sed, but all commands used in the shell script.
Hi
I executed the code
for file in `ls pdb*.ent`
do
new_name=`echo $file | sed 's/^pdb//;s/.ent/.txt/'`
mv $file $new_name
done
Its giving error at ' ls pdb*.ent' argument list too long
i have around 150000 entries
please help
Thank you (6 Replies)
I have a wrote a script which consits of the below line.. Below of this script I'm getting this error "ksh: /usr/bin/ls: arg list too long"
The line is
log_file_time=`ssh -i $HOME/.ssh/id_rsa -q $i ls -lrt /bp/karthik/test/data/log/$abc*|tail -1|awk '{print $8}'`
And $abc alias is as "p |... (1 Reply)
Hi guys
Following command results in
sed -i 's/#/\\#/g' /home/test/sqlstents*
-bash: /bin/sed: Argument list too long
Please help me solve it.. is there any other way i can do this?.. thanks (4 Replies)
I have a huge set of files (with extension .common) in my directory around 2 million. When I run this script on my Linux with BASH, I get /bin/awk: Argument list too long
awk -F'\t' '
NR == FNR { a=NR }
NR != FNR {
sub(".common", "", FILENAME)
print a, FILENAME, $1
}
'... (1 Reply)
Dear Friends,
The following script processes a 14508 lines log file.
#!/bin/sh
while read line
do
d=`sed 's/* - * \*\/*\/* *\)\] .*/\1/' | tr '/' ' ' | sed 's/\(*\):\(*\)/\1 \2/'`
y=`date -d "${d}" "+%Y%m%d%H%M%S"`
echo "${y}"
done
While running the above script, I am... (4 Replies)
Dear Experts,
I have a list of 10K files in a directory. I am not able to execute any commands lile ls -lrt, awk, sed, mv, etc........
I wanna execute below command and get the output. How can I achieve it?? Pls help.
root# awk -F'|' '$1 == 1' file_20120710* | wc -l
/bin/awk: Argument list... (2 Replies)
Hi,
i am having some trouble with the below command, can some one suggest me the better way to do it.
grep -l 'ReturnCode=1' `find $Log -newer /tmp/Failed.tmp -print | xargs ls -ld | egrep SUB | egrep -ve 'MTP' -ve 'ABC' -ve 'DEF' -ve 'JKL' -ve 'XYZ' | awk '{print $9}'` > $Home1
Its... (2 Replies)
Hi I am using find command --
find "directory1" -type f | xargs -i mv {} "directory2"
to avoid above argument list too long problem.
But, issue i am facing is directory1 is having subdirectories due to this i am facing directory traversal problem as i dont want to traverse subdirectories... (9 Replies)
Hi all,
I am using GNU sed (named gsed under macports) in OSX. I have a directory with a series of files named pool_01.jpg through pool_78802.jpg. I am trying to use this command to rename the files to their checksum + extension.
md5sum * | gsed -e 's/\(*\) \(.*\(\..*\)\)$/mv -v \2 \1\3/e'
... (3 Replies)
Hi Team,
Here's the situation.
I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir
mv /appl/abcd/work_dir /appl/abcd/process_dir
The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)