Hi Friends,
Can anyone help me with this:
To get the count of files that are existing in a directory created on a perticular date like in the example (01/08) .(having same pattern for the filename)
ex:
FileName Creted Date
FILE001 01/08/2007
FILE005 ... (6 Replies)
I am using ksh93 on Solaris.
Ok, this may seem like a simple request at first. I have a directory that contains sets of files with a YYYYMMDD component to the name, along with other files of different filespecs. something like this:
20110501_1.dat
20110501_2.dat
20110501_3.dat... (2 Replies)
Hi,
I have a file with 4 million rows. what i am trying to achieve is for every 1000 interval count the number of rows and display it
i/p
12
200
400
750
1000
1500
1800
2200
2345
2600
2896
3020
3400 (0 Replies)
Hello,
I need some sort of way to extract every date contained in a file, and count how many of those dates there are.
Here are the specifics:
The date format I'm looking for is mm/dd/yyyy
I only need to look after line 45 in the file (that's where the data begins)
The columns of... (2 Replies)
I have file listed like below
-rw-r--r--+ 1 test test 17M Nov 26 14:43 test1.gz
-rw-r--r--+ 1 test test 0 Nov 26 14:44 test2.gz
-rw-r--r--+ 1 test test 0 Nov 27 10:41 test3.gz
-rw-r--r--+ 1 test test 244K Nov 27 10:41 test4.gz
-rw-r--r--+ 1 test test 17M Nov 27 10:41 test5.gz
I... (5 Replies)
My unix version is IBM AIX Version 6.1
I tried google my requirement and found the below answer,
find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20"
But newer command is not working in AIX version 6.1 unix
I have given my requirement below:
Input:
atr files:
... (1 Reply)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
Discussion started by: lnemitz
2 Replies
LEARN ABOUT CENTOS
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do rtl layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter, a4. Default is A4.
--bottom-margin=bm
Set bottom margin in postscript points (1/72 inch). Default is 36.
--top-margin=tm
Set top margin. Default is 36.
--left-margin=lm
Set left margin. Default is 36.
--right-margin=rm
Set right margin. Default is 36.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--encoding=ENCODING
Assume the documentation encoding is ENCODING.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)