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Top Forums Shell Programming and Scripting How to use if/else if with substr? Post 302896083 by newbie2010 on Friday 4th of April 2014 09:56:20 AM
Old 04-04-2014
Thanks!

Belated, but I found this out right before your post, MadeInGermany. But thanks for confirming. Sometimes it's hard to see those punctuation marks! Everything works now.

Thanks, All!
 

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CTYPE_PUNCT(3)								 1							    CTYPE_PUNCT(3)

ctype_punct - Check for any printable character which is not whitespace or an alphanumeric character

SYNOPSIS
bool ctype_punct (string $text) DESCRIPTION
Checks if all of the characters in the provided string, $text, are punctuation character. PARAMETERS
o $text - The tested string. RETURN VALUES
Returns TRUE if every character in $text is printable, but neither letter, digit or blank, FALSE otherwise. EXAMPLES
Example #1 A ctype_punct(3) example <?php $strings = array('ABasdk!@!$#', '!@ # $', '*&$()'); foreach ($strings as $testcase) { if (ctype_punct($testcase)) { echo "The string $testcase consists of all punctuation. "; } else { echo "The string $testcase does not consist of all punctuation. "; } } ?> The above example will output: The string ABasdk!@!$# does not consist of all punctuation. The string !@ # $ does not consist of all punctuation. The string *&$() consists of all punctuation. NOTES
Note If an integer between -128 and 255 inclusive is provided, it is interpreted as the ASCII value of a single character (negative val- ues have 256 added in order to allow characters in the Extended ASCII range). Any other integer is interpreted as a string contain- ing the decimal digits of the integer. SEE ALSO
ctype_cntrl(3), ctype_graph(3). PHP Documentation Group CTYPE_PUNCT(3)
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