04-02-2014
We've had this conversation four or five times. You have a hard time telling when you are modifying the pointer instead of its contents. But the compiler can tell you that easily, so I have a suggestion:
Whenever you do char *mem=malloc(300); ...do this instead: char * const mem=malloc(300); This will make the mistake you keep repeating a compiler error -- "assignment of read-only variable". (It of course sets it, once, when you declare it. But thereafter it's considered 'fixed'.)
You are still free to modify its contents, like with strcpy(mem, originalstring) or mem[5]='Q' or *(mem+5)=37 or any other way you please. But if you try to alter the pointer that's an error. You can understand "assignment of read-only value" to mean "whoops, I mixed up a pointer's value and its contents".
If you find yourself needing to do complicated circumlocutions to get around 'assignment of read only variable', you can be fairly sure you've taken a wrong turn somewhere.
Last edited by Corona688; 04-02-2014 at 03:34 PM..
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