04-02-2014
Thanks!
it means it will work on for 11th and 12th month also right..
if [ "$month" -le "10" ] ; then
pmonth=0`echo $month`
else
pmonth=`echo $month`
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LEARN ABOUT PHP
intlcalendar.setfirstdayofweek
INTLCALENDAR.SETFIRSTDAYOFWEEK(3) 1 INTLCALENDAR.SETFIRSTDAYOFWEEK(3)
IntlCalendar::setFirstDayOfWeek - Set the day on which the week is deemed to start
Object oriented style
SYNOPSIS
public bool IntlCalendar::setFirstDayOfWeek (int $dayOfWeek)
DESCRIPTION
Procedural style
bool intlcal_set_first_day_of_week (IntlCalendar $cal, int $dayOfWeek)
Defines the day of week deemed to start the week. This affects the behavior of fields that depend on the concept of week start and end
such as IntlCalendar::FIELD_WEEK_OF_YEAR and IntlCalendar::FIELD_YEAR_WOY.
PARAMETERS
o $cal
- The IntlCalendar resource.
o $dayOfWeek
- One of the constants IntlCalendar::DOW_SUNDAY, IntlCalendar::DOW_MONDAY, , IntlCalendar::DOW_SATURDAY.
RETURN VALUES
Returns TRUE on success. Failure can only happen due to invalid parameters.
EXAMPLES
Example #1
IntlCalendar.setFirstDayOfWeek(3)
<?php
ini_set('date.timezone', 'Europe/Lisbon');
ini_set('intl.default_locale', 'es_ES');
$cal = IntlCalendar::createInstance();
$cal->set(2013, 5 /* June */, 30); // A Sunday
var_dump($cal->getFirstDayOfWeek()); // 2 (Monday)
echo IntlDateFormatter::formatObject($cal, <<<EOD
week of month : 'W'
week of year : 'ww
EOD
), "
";
$cal->setFirstDayOfWeek(IntlCalendar::DOW_SUNDAY);
echo IntlDateFormatter::formatObject($cal, <<<EOD
week of month : 'W'
week of year : 'ww
EOD
), "
";
The above example will output:
int(2)
local day of week: 7
week of month : 4
week of year : 26
local day of week: 1
week of month : 5
week of year : 27
PHP Documentation Group INTLCALENDAR.SETFIRSTDAYOFWEEK(3)