Hi,
I need to extract only a part of the filenames of some files. The files are named this way :
.tap_profile_SIT02
I want the "SIT02" part, which is not the same for each file. I was able to get what I want with bash, but not with ksh. Here is the command I used in bash :
find... (8 Replies)
Hi, i have a filename CRED20102009.txt in a server
20102009 is the date of the file ddmmaaaa format
the complete route is
/dprod/informatica/Fuentes/CRED20102009.csv
i want to extract the date to create a new file named Parameters.txt
I need to create Parameters.txt with this... (6 Replies)
I have lots of files in this format:
dvgrab-2003.06.29_15-30-24.mpg
The numbers represents the date and time (YYYY.MM.DD_HH-MM-SS)
How can I extract the dates from the filenames, and use the dates in the file timestamp?
I guess this can be done by using "find", "sed" and "touch"?
Can... (6 Replies)
Hi All,
I'm trying to get part of a filename and my skill with regular expression are lacking. I know I need to use SED but have no idea how to use it. I'm hoping that someone can help me out. The file names would be:
prefix<partwewant>suffix.extension
the prefix and suffix are always 3... (4 Replies)
Hi All,
Thanks in Advance
I am working on a shell script. I need some assistance.
My Requirement:
1) There are some set of files in a directory like given below
OTP_UFSC_20120530000000_acc.csv
OTP_UFSC_20120530000000_faf.csv
OTP_UFSC_20120530000000_prom.csv... (0 Replies)
Hi All,
Thanks in Advance
I am working on a shell script. I need some assistance.
My code:
if
then
set "subscriber" "promplan" "mapping" "dedicatedaccount" "faflistSub" "faflistAcc" "accumulator"\
"pam_account";
for i in 1 2 3 4 5 6 7 8;... (0 Replies)
Hi All,
Thanks in Advance
Shell Script or Perl Script
I am working on a shell script. I need some assistance.
My Requirement:
1) There are some set of files in a directory like given below
OTP_UFSC_20120530000000_acc.csv
OTP_UFSC_20120530000000_faf.csv... (7 Replies)
Hi,
I am writing an ebuild for Gentoo Linux operating system.
Writing an ebuild is about Bash scripting where I am a newbie.
So, my ebuild must find a part of a specific filename.
Such a filaname my look like this:
libvclient_release_x64.so.740and I must to find the number at the and of... (18 Replies)
Hi,
I'm totally new in sell script and working with a shell code. I want to extract the date and time from the filenames. The filenames are different but all of them begins with WI_ SCOPE_:
WI_SCOPE_DATA_CHANGE_2017-09-12_15-30-40.txt
WI_SCOPE_BACK_COMPLETE_QUEUE_2017-09-12_15-31-40.txt... (5 Replies)
Hi,
I am facing one scenario in which I need to extract exact position of date and time from the name of the files. For example, Below is the record in which I need to extract position of YYYYMMDD,HHMISS and YYMMDD. Date and time variables can come more than once. I need to use these position... (13 Replies)
Discussion started by: Prathmesh
13 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)