Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Sudoers for one day per week? Post 302895384 by Neo on Monday 31st of March 2014 02:52:01 PM
Old 03-31-2014
Not sure if I'm right or wrong... works for me but maybe that's a bug and not a feature!

Anyhow... each user should check his own system to insure it works however they edit it, of course.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Calculating the day of the week

Hi all, I would like to calculate the day of the week using a supplied date. i.e. 20011012 = Day 5. Any ideas? Many thanks, ligs (4 Replies)
Discussion started by: ligs
4 Replies

2. Programming

Function that gets the day of the week (0-6) ??

Hi , I am working at Unix system,using c lang. I need c fun which return the day of the week . For example : 0- Sunday. 1- Monday. .... 10x. (4 Replies)
Discussion started by: kamil
4 Replies

3. Shell Programming and Scripting

Yesterday's Day of week

I need o get yesterday's day of week but im not exactly sure. the actual name is what i want. I can do it with numbers but im not sure with words. (3 Replies)
Discussion started by: rcunn87
3 Replies

4. UNIX for Dummies Questions & Answers

Changing First Day Of The Week?

Hi All, Our system is running on Solaris 8 and we are using US locale. By default the First Day Of Week is Sunday, is it possible for us to change it to Monday? I have googled it but found very little of use. THanks in advance. (2 Replies)
Discussion started by: fowlerleftfoot
2 Replies

5. HP-UX

Get Day of Week from date

Hi All, I have date in string format 'YYYY-MM-DD'. I want to know day of the week for this date. Example. For '2005-08-21' my script should return '0' or Sunday For '2005-08-22' it should return '1' or Monday I want piece of code for HP-UX korn shell. Appreciate reply on this. (5 Replies)
Discussion started by: vpapaiya
5 Replies

6. UNIX and Linux Applications

Day of week different in windows and Linux

Hi all, My program is getting date from database (oracle) and am getting that date's day of week also. In windows its giving one number and different in linux ;) For Example: 30 - Jun - 2009 Am getting 2 in windows and 3 in Linux. Am not understanding whats going wrong.. Am... (3 Replies)
Discussion started by: rajinavaneethan
3 Replies

7. Shell Programming and Scripting

Get day of week from cal

Hi all, I am trying to get dow from cal using below script #! /bin/bash YEAR=`echo $1 | cut -c 1-4` MONTH=`echo $1 | cut -c 5-6` DAY=`echo $1 | cut -c 7-8` for i in 1 2 3 4 5 6 7 do dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'` echo $dayofweek... (4 Replies)
Discussion started by: bzylg
4 Replies

8. UNIX for Dummies Questions & Answers

Day of the week from a string

Hi All, I need to know how to derive the day of the week by passing the value in following format: Feb 28 2010 The output I'm expecting is Sunday or Sun. I know, I can use the following code to get the day of the week. date +%a But I want to pass the value as a string. Please help... (11 Replies)
Discussion started by: shash
11 Replies

9. HP-UX

Find Day of Week

In HP-UX the date command does not have the "-d" switch like some other *nixes do. I'm working a simple script to tell me, given the day, month and year what day of the week that falls on. Assuming valid day, month and year input (I'd perform quality checks on the input separately, but not... (5 Replies)
Discussion started by: rwuerth
5 Replies

10. Shell Programming and Scripting

Get the week's day

Hi All, I have the below requirement , if i give the week number for ex 41 i need to get the date for Monday and thursday for this given week. my expected output is 13/10/2014 (Monday's date) and 16/10/2014 (Thursday's date) I am using GNU LINUX . Pls help me with your thoughts. Thanks in... (7 Replies)
Discussion started by: mohanalakshmi
7 Replies
Catalyst::Plugin::Authorization::Roles(3pm)		User Contributed Perl Documentation	       Catalyst::Plugin::Authorization::Roles(3pm)

NAME
Catalyst::Plugin::Authorization::Roles - Role based authorization for Catalyst based on Catalyst::Plugin::Authentication SYNOPSIS
use Catalyst qw/ Authentication Authorization::Roles /; sub delete : Local { my ( $self, $c ) = @_; $c->assert_user_roles( qw/admin/ ); # only admins can delete $c->model("Foo")->delete_it(); } DESCRIPTION
Role based access control is very simple: every user has a list of roles, which that user is allowed to assume, and every restricted part of the app makes an assertion about the necessary roles. With "assert_user_roles", if the user is a member in all of the required roles access is granted. Otherwise, access is denied. With "assert_any_user_role" it is enough that the user is a member in one role. There are alternative approaches to do this on a per action basis, see Catalyst::ActionRole::ACL. For example, if you have a CRUD application, for every mutating action you probably want to check that the user is allowed to edit. To do this, create an editor role, and add that role to every user who is allowed to edit. sub edit : Local { my ( $self, $c ) = @_; $c->assert_user_roles( qw/editor/ ); $c->model("TheModel")->make_changes(); } When this plugin checks the roles of a user it will first see if the user supports the self check method. When this is not supported the list of roles is extracted from the user using the "roles" method. When this is supported, the "check_roles" method will be used to delegate the role check to the user class. Classes like the one provided with iCatalyst::Authentication::Store::DBIx::Class optimize the check this way. METHODS
assert_user_roles [ $user ], @roles Checks that the user (as supplied by the first argument, or, if omitted, "$c->user") has the specified roles. If for any reason ("$c->user" is not defined, the user is missing a role, etc) the check fails, an error is thrown. You can either catch these errors with an eval, or clean them up in your "end" action. check_user_roles [ $user ], @roles Takes the same args as "assert_user_roles", and performs the same check, but instead of throwing errors returns a boolean value. assert_any_user_role [ $user ], @roles Checks that the user (as supplied by the first argument, or, if omitted, "$c->user") has at least one of the specified roles. Other than that, works like "assert_user_roles". check_any_user_role [ $user ], @roles Takes the same args as "assert_any_user_role", and performs the same check, but instead of throwing errors returns a boolean value. SEE ALSO
Catalyst::Plugin::Authentication Catalyst::ActionRole::ACL Catalyst::Manual::Tutorial::06_Authorization AUTHOR
Yuval Kogman <nothingmuch@woobling.org> COPYRIGHT &; LICENSE Copyright (c) 2005-2011 the Catalyst::Plugin::Authorization::Roles "AUTHOR" as listed above. This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself. perl v5.14.2 2011-04-29 Catalyst::Plugin::Authorization::Roles(3pm)
All times are GMT -4. The time now is 09:51 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy