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Full Discussion: Splitting file - custom req.
Top Forums Shell Programming and Scripting Splitting file - custom req. Post 302894396 by bijou on Tuesday 25th of March 2014 10:58:55 AM
Old 03-25-2014
Quote:
Originally Posted by vbe
Well I would use awk...
What have you tried? search the forums, because there are plenty of similar posts here...
I tried to use split command, some loops but I couldn't get the point.
I was also searching on this forum (and some others) but couldn't find anything like this. (fact, there is plenty of similar cases..but not this one).

---------- Post updated at 09:19 AM ---------- Previous update was at 09:15 AM ----------

Quote:
Originally Posted by bartus11
Try:
Code:
awk -F"|" -v OFS="|" '{x=$4;y=$5;NF=3;print > "MYFILE_"x"_"y".dat"}' My_file.dat

That works amazing Smilie
Big thanks to You!SmilieSmilie

---------- Post updated at 09:58 AM ---------- Previous update was at 09:19 AM ----------

Quote:
Originally Posted by bartus11
Try:
Code:
awk -F"|" -v OFS="|" '{x=$4;y=$5;NF=3;print > "MYFILE_"x"_"y".dat"}' My_file.dat

Let me just ask last question.

I need to add a current date YYYYMMDD to filename. So, finally it should be:

MYFILE_YYYYMMD_x_y.dat
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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