thanks a lot the first one works and displays the date as i want but please tell me how do i create a directory using that..
ie
so in this command how do i put it
Last edited by Scrutinizer; 03-15-2014 at 12:50 PM..
Reason: code tags
I have a folder structure like the below
/test/test1/test2/app
/test/test3/app
/test/test4/test5/app
..
I need to create a new folder under "app" in all the above listed directory structure at one shot by the name "subapp" .
How can we acheive this using a script .
New to unix... (4 Replies)
Hi guys i have written a script which takes the options given to him and execute itself accordingly.
for example
if a script name is doctortux then executing doctortux without option should made doctortux to be executed in automatic mode i.e. doctortux -a
or if a doctortux is needed to run in... (4 Replies)
It is for HP-Unix B.11.31.
Requirement:
1. List the directories, which directories name has given particular string.
Example: Directories with name "Build"
2. On the output of 1. list the directories by creation date as sort order.
I tried with; find . -type d -name "Build*"
... (3 Replies)
Hi,
In the Unix Box, I have a situation, where there is folder name called "Projects" and in that i have 20 Folders S1,S2,S3...S20. In each of the Folders S1,S2,S3,...S20 , there is a same name folder named "MP". So Now, I want to get all the files in all the "MP" Folders and write all those... (6 Replies)
I am trying to link 2 directories using:
ln -s /net/<hostname>/srcdir/ /net/<desthostname>/dstdir/
I get the following error:
ln: /net/<desthostname>/dstdir: Function is not available
What is it that i am trying to do wrongly in the above operation?
Please use next time code tags (3 Replies)
I have a top-level directory called work and I would like to create subdirectories work1 work2... under this directory. Also I would like to create subdirectory under work1 -- test, work2 -- test etc., Can I automate this using a command-line script?
work
|_work 1
|_test
|_work 2
... (2 Replies)
Sorry, about this thread - I solved my own problem! Thanks for taking a look.
edit by bakunin: no problem, but it would have been a nice touch to actually tell us what the solution was. This would have been slightlich more educating than just knowing that you found it.
I changed your title to... (0 Replies)
It is for HP-Unix B.11.31.
Requirement:
1. List the directories, having given pattern in the directories name, sorted by creation date.
Example: Directories with name "pkg32*" or "pkg33*"
2. On the output of 1. list the directories by creation date as sort order, with creation date... (2 Replies)
Hi i have two directories and files inside them
Directory 1:
Directory 2:
These files are the same but song.mp3 in Directory 1 is newer than song.mp3 in Directory 2, and work.txt in Directory 2 is newer than work.txt in Directory 1.
Now is my question. How i can compare these files... (10 Replies)
Discussion started by: Falstaff
10 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)