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Full Discussion: Sort String using awk
Top Forums Shell Programming and Scripting Sort String using awk Post 302892471 by Scrutinizer on Wednesday 12th of March 2014 07:39:59 PM
Old 03-12-2014
Bubble sort an array inside the function, which calls an array by reference, so the arrays are sorted afterwards. Then compare arrays outside the function.
Code:
snamelist="AAAB,ABCddf,LMNS,PQR:VALUE1 AAB,ABSSf,LMNS,DFD:VALUE2 LMNS,ABCddf,PQR,AAAB:VALUE3"
BASELINE="AAAB,ABCddf,LMNS,PQR"

printf "%s\n" $snamelist | 
awk -F: -v baseline="$BASELINE" '
  function arrsort(A,	n,i,c){
    n=length(A)
    do {
      c=""; 
      for(i=1;i<n;i++) {
        if(A[i]>A[i+1]) {
          c=A[i]; A[i]=A[i+1]; A[i+1]=c
        }
      }
    }
    while(c!="")
  }

  BEGIN{
    split(baseline,B,/,/)
    arrsort(B)
  }

  {
    split($1,F,/,/)
    arrsort(F)
    svcstatus="OK"
    for(i in F) if(B[i]!=F[i]) svcstatus="NOT-OK"
    printf "%s %s %s %s\n", $0, $1, baseline, svcstatus
  }
'

This is using a sorting method, but since the only goal is to find out if all values are present in both strings, it seems to me that this could also be done without sorting...



--
@shamrock: if (sortme(srt_pref, m) == sortme(srt_baseline, n)) is always true, no? Since the output of the sortme function is always an empty string..

Last edited by Scrutinizer; 03-12-2014 at 09:20 PM..
 

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