Convert epoch time stamp into human readable format Post: 302892415

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I am trying to create a script that will take epoch (input from command line) and convert it into a readable format in bash/shell ---------- Post updated at 08:03 PM ---------- Previous update was at 07:59 PM ---------- #!bin/bash read -p "Please enter a number to represent epoch time:"...

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getdate

GETDATE(1)							   User Commands							GETDATE(1)

NAME

       getdate - AME

SYNOPSIS

       [-dv][-n dec][-f format] [ra dec sys] itype2otype [date and/or time]

DESCRIPTION

       Convert date and time between various formats

	      [-dv][-n dec][-f format] itype2otype @file

	      itype: nfd=ISOFITS fd=FITS, dt=yyyy.mmdd, hr=hh:mm:ss, deg=dd:mm:ss

	      jd=Julian  Date,	mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD ep=epoch, epj=Julian epoch, epb=Besselian
	      epoch lt=local time, ut=UT, ts=seconds since 1950-01-01 now=current time, ang=fractional degrees

	      otype: fd=FITS, dt=yyyy.mmdd, jd=Julian Date, mjd=Modified Julian Date

	      hjd=Heliocentric Julian Date, mhjd=Modified HJD  hr=hh:mm:ss,  deg=dd:mm:ss,  ang=fractional  degrees  ep=epoch,	epj=Julian  epoch,
	      epb=Besselian epoch ts=seconds since 1950-01-01, tsu=Unix sec, tsi=IRAF sec gst=Greenwich Sidereal Time, lst=Local Sidereal Time

	      @file: First one or two columns are in itype format ra dec sys:  Need for Heliocentric conversions

       -a: Append date to input file, if there is one

       -d: Print date without time

       -e: Print output as ET/TDT/TT converting from UT

       -f: Format for output number (C printf)

       -h hours: Longitude in hours, west positive

       -l degrees: Longitude in degrees, west positive

       -n: Number of decimal places in sec, epoch, JD

       -t: Print time without date

       -v: Verbose

getdate 3.8.4							     June 2012								GETDATE(1)

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