I'm using the below command to list files older than 2 hours but it returns redundant output, am I missing something.
# find . -mmin +120 -exec ls -l {} \;
total 0
-rw-r--r-- 1 root system 0 Oct 13 09:52 test1
-rw-r--r-- 1 root system 0 Oct 13 09:52 test2
-rw-r--r-- 1 root ... (5 Replies)
I am using the following command:
nawk -F"," 'NR==FNR {a=$1;next} a {print a,$1,$2,$3}' file1 file2
I am getting 40 records output.
But when i import file1 and file2 in MS Access i get 140 records.
And i know 140 is correct count.
Appreciate your help on correcting the above script (5 Replies)
Hello,
I couldn't find anything on the Forum that would help me to solve this problem. Could any body help me process below data using awk?
I have got two files:
file1:
Worker1: Thomas
Position: Manager
Department: Sales
Salary: $5,000
Worker2: Jason
Position: ... (5 Replies)
cat T|awk -v format=$format '{ SUM += $1} END { printf format,SUM}'
the file T has below data
usghrt45tf:hrguat:/home/hrguat $ cat T
-1363000.00123456789
-95000.00789456123
-986000.0045612378
-594000.0015978
-368939.54159753258415
-310259.0578945612
-133197.37123456789... (4 Replies)
Hi All,
I am looking to filter out filesystems which are greter than a specific value.
I use the command
df -h | awk '$4 >=70.00 {print $4,$5}'
But this results out as below, which also gives for lower values.
9% /u01
86% /home
8% /u01/data
82% /install
70% /u01/app
Looks... (3 Replies)
The awk below is supposed to count all the matching $5 strings and count how many $7 values is less than 20. I don't think I need the portion in bold as I do not need any decimal point or format, but can not seem to get the correct counts. Thank you :).
file
chr5 77316500 77316628 ... (6 Replies)
Hello scripting geeks,
I am new to scripting and facing some issues in writing the logic of the script. Request your kind help here
Actually when i run a command i get o/p as below
o/p :
0x0000
0x0000
0x0000
0x0000
0x0000
0x0000
these are hex values i guess...now i want to... (15 Replies)
I was wondering whether anyone has any idea what is happening here. I'm using simple code to compare 2 tab delimited files based on column 1 values. If the column1 value of file1 exists in file2, then I'm to print the column4 value in file2 in column3 of file1. Here is my code:
1st I have to... (6 Replies)
Discussion started by: Geneanalyst
6 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)