You didn't even come close to answering my question. In the script:

Code:

rsh $HOST 'nohup $process.sh >/dev/null > 2>&1 &'

The rsh utility runs the command nohup $process.sh >/dev/null > 2>&1 & on the host specified by the expansion of$HOST. Since the string $process is given to rsh inside single quotes, $process will be expanded on the system specified by the expansion of $HOST; not on the system where you run the rsh command.

I repeat my question: What defines the value that $process will expand to on the hosts ws1, ws2, and ws3.

If process is being defined on the system where you're running rsh and not on ws1, ws2, and ws3, the command you're running on those systems is:

Code:

nohup .sh >/dev/null > 2>&1 &

Do you have any proof that the program that you want to run on ws1, ws2, and ws3 has been started?

Try running:

Code:

rsh $HOST 'nohup $process.sh >/dev/null > &'

which is likely to be a syntax error, but now you stand a chance of seeing the syntax error. Then try running:

Code:

rsh $HOST 'nohup $process.sh >/dev/null &'

which doesn't have any syntax errors, but I'm expecting you'll see an error message something like:

Code:

.sh not found

Then try running:

Code:

rsh $HOST "nohup $process.sh >/dev/null > 2>&1 &"

which will expand both $HOST and $process on the local system.