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Shell Programming and Scripting
[Solved] For loop help
Post 302890672 by ahmedwaseem2000 on Thursday 27th of February 2014 09:23:23 PM
02-27-2014
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The code at the bottom is a simplified example of what we have.
If I use the following:
&& echo "echo failed"
$? returns 1
When I use
if ; then echo "echo failed" ; fi
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LEARN ABOUT NETBSD
zfgrep
ZGREP(1) BSD General Commands Manual ZGREP(1) NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD