02-23-2014
I don't have working code for this. To make the example simpler, the algorithm should look for any pattern of length 6 of letters A C E G in any order and find the most abundant pattern across the entire column.
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LEARN ABOUT PHP
substr_count
SUBSTR_COUNT(3) 1 SUBSTR_COUNT(3)
substr_count - Count the number of substring occurrences
SYNOPSIS
int substr_count (string $haystack, string $needle, [int $offset], [int $length])
DESCRIPTION
substr_count(3) returns the number of times the $needle substring occurs in the $haystack string. Please note that $needle is case sensi-
tive.
Note
This function doesn't count overlapped substrings. See the example below!
PARAMETERS
o $haystack
- The string to search in
o $needle
- The substring to search for
o $offset
- The offset where to start counting
o $length
- The maximum length after the specified offset to search for the substring. It outputs a warning if the offset plus the length is
greater than the $haystack length.
RETURN VALUES
This function returns an integer.
CHANGELOG
+--------+-----------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+-----------------------------------------------+
| 5.1.0 | |
| | |
| | Added the $offset and the $length parameters |
| | |
+--------+-----------------------------------------------+
EXAMPLES
Example #1
A substr_count(3) example
<?php
$text = 'This is a test';
echo strlen($text); // 14
echo substr_count($text, 'is'); // 2
// the string is reduced to 's is a test', so it prints 1
echo substr_count($text, 'is', 3);
// the text is reduced to 's i', so it prints 0
echo substr_count($text, 'is', 3, 3);
// generates a warning because 5+10 > 14
echo substr_count($text, 'is', 5, 10);
// prints only 1, because it doesn't count overlapped substrings
$text2 = 'gcdgcdgcd';
echo substr_count($text2, 'gcdgcd');
?>
SEE ALSO
count_chars(3), strpos(3), substr(3), strstr(3).
PHP Documentation Group SUBSTR_COUNT(3)