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Top Forums Shell Programming and Scripting Manipulating column in a file in UNIX Post 302887828 by sea on Tuesday 11th of February 2014 04:40:34 AM
Old 02-11-2014
To get a little practice myself....

Code:
OLD_IFS="$IFS"
IFS="|"
while read ColA ColB ColC ColD;do
    newB=$(echo "$ColB / 2" | bc)
    printf "$IFS$ColA$IFS$newB$IFS$ColC$IFS$ColD"
done
IFS="$OLD_IFS"

Hope this helps
 

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DB2_FIELD_NAME(3)							 1							 DB2_FIELD_NAME(3)

db2_field_name - Returns the name of the column in the result set

SYNOPSIS
string db2_field_name (resource $stmt, mixed $column) DESCRIPTION
Returns the name of the specified column in the result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns a string containing the name of the specified column. If the specified column does not exist in the result set, db2_field_name(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_NAME(3)
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