I have a date that looks like this:
2008/100:18:40:47.040
I need it to look like this:
2008 04 09 18 40 47 040
I have looked at datecalc and it doesn't seem like it takes the day of year for this year (or whatever year is input) and converts it into month and day. It also has to account... (2 Replies)
Hi,
I'm working on a Informix4gl module. I'm just trying to find out any built-in function to fetch only the year/month from an INTERVAL YEAR TO MONTH data value.
Please let me know, if there are any functions to do this. If not, let me know for any alternative solutions to attain this.
... (5 Replies)
Hi
I have files like
abc_cd_20110302_123423
abc_cd_ef_20110301_123423
abc_cd_ef_20110403_123423
abc_ef_20110401_123423
I want to extract the
the year and month associated with each file.
I tried
logfileyearmonth=`echo $logfile | awk -F_'{print $NF}'`
Any other way can I... (6 Replies)
Discussion started by: dgmm
6 Replies
6. Forum Support Area for Unregistered Users & Account Problems
So why does the password reset page tell me I've answered the question incorrectly?
First, I tried to register. Never received an email. So I tried to register with a different email/username. I was told it was taken. I tried to have a password sent to my email, but June is not the 6th month... (1 Reply)
Hi All,
I find all files for same month and year
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 21 2012 d.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 2012 f.txt
-rwxr-xr-x 1... (8 Replies)
Hi All,
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 a.txt
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 b.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 2012 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 24 2012 d.txt... (16 Replies)
The following bash command line works for the last day of the month. Test by replacing the 1 with tomorrows day of month number
&& echo "Day before tomorrow"Can it be used within crontab? As
* * 28-31 * * && echo "Today ls last day of month" >>/tmp/crontabtestI tried to test crontab with... (1 Reply)
Discussion started by: lsatenstein
1 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)