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Top Forums Shell Programming and Scripting Searching and printing the only pattern using awk,sed or perl Post 302886226 by omkar.jadhav on Thursday 30th of January 2014 07:30:20 AM
Old 01-30-2014
great but the output of the script as as below :

Code:
 
$ lparstat -i | grep -w "Entitled Capacity" | awk 'gsub(/[a-zA-Z]/,X,$0) gsub(/[[:punct:]]/,Y,$0)'
                            100
                      1900

i was looking to grep only the below line :

PHP Code:
Entitled Capacity                          1.00 
out of the below output :

PHP Code:
lparstat -grep -"Entitled Capacity"
Entitled Capacity                          1.00
Entitled Capacity of Pool                  
1900 
Could you guide me how can to do that...output should be:
Entitled Capacity : 1.00

script should search for pattern "Entitled Capacity" only.

please let me know how can this be achived .
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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