Unable to pass shell script variable to awk command in same shell script
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
Code:
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new
I also tried below options but no success, please suggest.
Hi ,
i am beginner to Unix, I have one small script which execute java programme,it has java command input output structure . Right now i have given Input output structure manually that is on same directory, now how can i pass that by commandline
#!/bin/sh
java Classjava input.txt... (5 Replies)
Hi,
I have a shell script with an ambedded awk script.
i need to pass a script variable to the awk script.
Please help.
Thanks in advance
Himani (3 Replies)
Hello experts,
can I return a value from gawk to a shell script ?
My script as follows,
#Here I want the num value to shell script so that I can use later
gawk '
{
split($0,num,",");
print num
}'
gawk -v no=$number '{print no}'
file1
... (3 Replies)
Hello Experts,
Actually I was searching for a solution here in this forum , but didn't get what exactly I want . Is this possible to do in awk ?
I am trying to do some thing like below in ksh script . Upto my knowledge I can pass shell script to awk with "-v " option.
But I... (3 Replies)
This is my script structure
main script calls configure script which needs to be run as a different user and the configure script calls my application installation script. the application instruction script prompts the user for a directory which I need to pass from my main or configure script.
... (4 Replies)
Discussion started by: cmastays
4 Replies
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Variable I have in my shell script
diff=$1$2.diff
id=$2
new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new
I could see value of $id is not passing to the awk... (0 Replies)
I am trying to automate a testcase . I am installing some software and it waits for user input after displaying "Do you want to continue ? " I am trying to do this in shell scripting.
#!/bin/bash
#!/usr/bin/expect -f
/usr/bin/expect << EOF
spawn apt-get install openjdk-7-jdk
expect "*Do you... (1 Reply)
Hi All,
I am new to shell script. I am trying to pass value from .sh file to .sql file .
But I am able to run the .sql file from .sh file with values in sql file.
But I am unable to pass the values from .sh file. can some one please help to resolve this.
here is my .sh file
s1.sh
... (4 Replies)
Hi,
Please need to print the Rej variable outsite the awk script which is given below...please advised how to achieve it.
#!/bin/bash
echo "Enter DMU Pipe delimited File name for the Feed to be validated"
read DMU_File
echo "Enter Pre-DMU File name for the Feed"
read Predum_file
... (3 Replies)
I want to make a config file which contain all the paths.
i want to read the config file line by line and pass as an argument on my below function.
Replace all the path with reading config path line by line and pass in respective functions.
how can i achieve that?
Kindly guide.
... (6 Replies)
Discussion started by: sadique.manzar
6 Replies
LEARN ABOUT MINIX
diff
DIFF(1) General Commands Manual DIFF(1)NAME
diff - print differences between two files
SYNOPSIS
diff [-c | -e | -C n] [-br]file1 file2
OPTIONS -C n Produce output that contains n lines of context
-b Ignore white space when comparing
-c Produce output that contains three lines of context
-e Produce an ed-script to convert file1 into file2
-r Apply diff recursively to files and directories of
EXAMPLES
diff file1 file2 # Print differences between 2 files
diff -C 0 file1 file2
# Same as above
diff -C 3 file1 file2
# Output three lines of context with every
diff -c file1 file2 # Same
diff /etc /dev # Compares recursively the directories /etc and /dev
diff passwd /etc # Compares ./passwd to /etc/passwd
DESCRIPTION
the same name, when file1 and file2 are both directories" difference encountered"
Diff compares two files and generates a list of lines telling how the two files differ. Lines may not be longer than 128 characters. If
the two arguments on the command line are both directories, diff recursively steps through all subdirectories comparing files of the same
name. If a file name is found only in one directory, a diagnostic message is written to stdout. A file that is of either block special,
character special or FIFO special type, cannot be compared to any other file. On the other hand, if there is one directory and one file
given on the command line, diff tries to compare the file with the same name as file in the directory directory.
SEE ALSO cdiff(1), cmp(1), comm(1), patch(1).
DIFF(1)
01-27-2014
