Unable to pass shell script parameter value to awk command in side the same script
Variable I have in my shell script
I could see value of $id is not passing to the awk command, i also tried few options as below but no help. Please assist.
If I am passing the value directly in place of $id then it is working.
Thanks in advance.
Regards,
Ashutosh
Moderator's Comments:
Use code tags for code please. [code] stuff [/code]
Last edited by Corona688; 01-27-2014 at 12:15 PM..
if
then
# mail -s "Import failed file does not exist" sanjay.jaiswal@xyz.com
echo "FILE does not exist"
exit 1
fi
echo "FILE EXIST"
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Discussion started by: Vee
1 Replies
LEARN ABOUT X11R4
zcmp
ZDIFF(1) General Commands Manual ZDIFF(1)NAME
zcmp, zdiff - compare compressed files
SYNOPSIS
zcmp [ cmp_options ] file1 [ file2 ]
zdiff [ diff_options ] file1 [ file2 ]
DESCRIPTION
Zcmp and zdiff are used to invoke the cmp or the diff program on files compressed via gzip. All options specified are passed directly to
cmp or diff. If only file1 is specified, it is compared to the uncompressed contents of file1.gz. If two files are specified, their con-
tents (uncompressed if necessary) are fed to cmp or diff. The input files are not modified. The exit status from cmp or diff is pre-
served.
SEE ALSO cmp(1), diff(1), zmore(1), zgrep(1), znew(1), zforce(1), gzip(1), gzexe(1)BUGS
Messages from the cmp or diff programs may refer to file names such as "-" instead of to the file names specified.
ZDIFF(1)