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Full Discussion: Printf conversion specifiers
Top Forums Programming Printf conversion specifiers Post 302885100 by yifangt on Thursday 23rd of January 2014 12:42:45 PM
Old 01-23-2014
Printf conversion specifiers

Hello, this is one examples that I always panic with C printf format specifier.
1) I did read the manpage with
Code:
 man 3 printf
...... One can also specify explicitly which argument is taken, at each place where an argument  is  required,  by  writing
       "%m$"  instead  of  '%'  and "*m$" instead of '*', where the decimal integer m denotes the position in the argument list of the desired
       argument, indexed starting from 1.  Thus,
           printf("%*d", width, num);
       and
           printf("%2$*1$d", width, num);
       are equivalent.  The second style allows repeated references to the same argument.

1) Can you please explain this example on width and num for me.
2) To have further understanding I used following code from "A book on C by Al Kelley/Ira Pohl, page 503" to test,
Code:
#include <stdio.h>

int main()
{
    int i;
    char c;
    char string[15];
    printf("Please input a line:\n"); 
    
   scanf("%d , %*s %% %c %5s %s", &i, &c, string, &string[5]);
    //input: 45 , ignore_this, % C read_in_this**
    
    printf("%d , %*s %% %c %5s %c", &i, &c, string, &string[5]);
    return 0;
}

but I met two problems. 1) A bunch of warnings as I mentioned in my last threads:
Code:
pg503.c: In function ‘main’:
pg503.c:13:2: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’ [-Wformat]
pg503.c:13:2: warning: field width specifier ‘*’ expects argument of type ‘int’, but argument 3 has type ‘char *’ [-Wformat]
pg503.c:13:2: warning: format ‘%c’ expects argument of type ‘int’, but argument 5 has type ‘char *’ [-Wformat]
pg503.c:13:2: warning: format ‘%s’ expects a matching ‘char *’ argument [-Wformat]
pg503.c:13:2: warning: format ‘%c’ expects a matching ‘int’ argument [-Wformat]

2) when I tried:
Code:
./a.out 
Please input a line:
45 , ignore_this, % C read_in_this**

Note: Spaces after 45, two asterisks were put at the end on purpose, and I was expecting to see:
Code:
45
, 
read_
in_this**

The program went infinite, nothing was printed. Thank you!

Last edited by yifangt; 01-23-2014 at 01:45 PM.. Reason: indentation
 

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