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Full Discussion: Unclear pointer and array
Top Forums Programming Unclear pointer and array Post 302884210 by Akshay Hegde on Saturday 18th of January 2014 11:58:34 AM
Old 01-18-2014
Could this help you ?

Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

main(){

int start = 3;
int stop  = 9;
const char src[] = "A test string";

// print 6 char from src+start 
printf("%.*s\n",stop-start, src + start);

// &src[3] == src+3
printf("%s %s\n", &src[3], src+3);

// what is src+start ?
printf("src + %d = %s\n",start,src+start);

// print nchar from src+start
int nchar = 9;
printf("%.*s\n",nchar, src + start);


}

Code:
$ gcc test2.c
$ ./a.out 
est st
est string est string
src + 3 = est string
est strin

---edit----

Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

main(){

int start = 3;
int stop  = 9;
const char src[] = "A test string";

// I confused from  variable "count" that whether you like to print "char-start to char-stop" '3 - 9' or n char from start ?
unsigned int count = stop - start;

// print 6 char from src+start 
printf("char %d-%d = %d ~ %.*s\n",start,stop,count,count, src + start);

// n char specified in stop from starting
printf("Total char %d from start ~ %.*s\n",stop,stop,src + start);


}

Code:
$ ./a.out 
char 3-9 = 6 ~ est st
Total char 9 from start ~ est strin


Last edited by Akshay Hegde; 01-18-2014 at 01:24 PM..
This User Gave Thanks to Akshay Hegde For This Post:
 

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STRCAT(3)						     Linux Programmer's Manual							 STRCAT(3)

NAME
strcat, strncat - concatenate two strings SYNOPSIS
#include <string.h> char *strcat(char *dest, const char *src); char *strncat(char *dest, const char *src, size_t n); DESCRIPTION
The strcat() function appends the src string to the dest string, overwriting the null byte ('') at the end of dest, and then adds a ter- minating null byte. The strings may not overlap, and the dest string must have enough space for the result. The strncat() function is similar, except that * it will use at most n characters from src; and * src does not need to be null-terminated if it contains n or more characters. As with strcat(), the resulting string in dest is always null-terminated. If src contains n or more characters, strncat() writes n+1 characters to dest (n from src plus the terminating null byte). Therefore, the size of dest must be at least strlen(dest)+n+1. A simple implementation of strncat() might be: char* strncat(char *dest, const char *src, size_t n) { size_t dest_len = strlen(dest); size_t i; for (i = 0 ; i < n && src[i] != '' ; i++) dest[dest_len + i] = src[i]; dest[dest_len + i] = ''; return dest; } RETURN VALUE
The strcat() and strncat() functions return a pointer to the resulting string dest. CONFORMING TO
SVr4, 4.3BSD, C89, C99. SEE ALSO
bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wcscat(3), wcsncat(3) COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
2008-06-13 STRCAT(3)
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