Hi All,
I want to find the previous day's date and store that in a variable, which will be usuful for further processing.
Any help please.
Regards,
raju (4 Replies)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
Hi,
I would like to write a script that checks if a file ('counter') was modified the previous day, if so erase its contents and write 00000000 into it.
For e.g. if the file 'counter' was last modified at 11.30pm on 24th May and the script runs at 12.15am of 25th May, it should erase it's... (1 Reply)
Hi All,
I have a requirement where I need to first capture the current day & move all the files from a particular directory based on a previous day.
i.e move all the files from one directory to another based on current day & a previous day. Here is what I am trying, but it gives me errors.... (2 Replies)
Hi All ,
I am trying to extract the day and month from a user supplied date . But not able .
Please help .
This is what I am trying to do , I have followed other articles in this scenario.
userdate=$1
echo "Script parameter userdate is $userdate"
The output of this is in this... (7 Replies)
Ok, the title is confusing i know, but it is a weird question.
I have a bash script running on Centos5.8 and want to find a better way to do some date manipulation. What i am trying to do is get 3 days of files (day before, that day, and day after), concatenate the three files and pass them on... (2 Replies)
Hi Gurus,
I would like to get the date for the previous year based on the date I specify.
For e.g. If I input today's date (i.e. 20130422) I need to get 20120422.
We don't have GNU and use K Shell. Any help is highly appreciated.
Thanks
Shash (4 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
Discussion started by: learner24
0 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)