I have below files in one location /test/files and also for each dates there are similar files
If i execute the script like this, ./script.sh it should copy previous day files (today-20140111, previous day - 20140110). File format as shown above) to another location /test/copied. I have a previous day function though.
On runnning script sh -x script.sh 20130924 it should copy all files for that date as shown above.
How to achieve both previous day copy and explicit date copy ??
Last edited by Don Cragun; 01-11-2014 at 10:37 AM..
Reason: Use ICODE tags(not italics) to display in-line code and CODE tags to display sample input files.
I need help in forming a script to copy files from one location which has a sub directory structure to another location with similar sub directory structure,
say location 1,
/home/rick/tmp_files/1-12/00-25/
here 1-12 are the number of sub directories under tmp_files and 00-25 are sub... (1 Reply)
Create a script that copies files from one specified directory to another specified directory, in the order they were created in the original directory between specified times. Copy the files at a specified interval. (2 Replies)
Hello all! I am trying to create a script that will copy files from one location, to another but only folders that are filled with thumbnails to an exact directory replica in the second location. For example:
/images/2012/01/19/Event/Photographer/thumbnails
to
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:EDIT:
I think my post name should have been labeled: how to copy files and record original file location. not "retain".
Hello, this is my first post! I searched the forums a lot before posting, but was unable to answer my question.
Here's my problem:
There are several hundred text files... (4 Replies)
Hi Gurus,
I am a newbie to shell scripting and I am facing a problem right now.I have to automate the copy of files based on a priority.The scenario is as below:
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Hello Experts,
I need to copy files from one location to another using xargs.
Tried something like this (In Ubuntu & Solaris ).
mkdir -p 1234;
find /home/emd/Desktop/n007/M007/ -type f -name "A2014*" | xargs -0 cp -r {} /home/emd/Desktop/1234
But every time i run this, a weird error... (6 Replies)
Discussion started by: Saidul
6 Replies
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Hi guys...please any one help me ....
how to copy files from source to target location
if 5 files copied successfully out of 10 files then implement success=10
and if remaining 5 files not copied successfully then count error=5
how to implement this condition with in loop
i need code linux... (0 Replies)
Hello there wonderful people,
I am running on Solaris 10 and with the following ksh version:
strings /bin/ksh | grep Version | tail -2
@(#)Version M-11/16/88i
Suppose I want to copy files that end in _v2 from underneath /dir1/dir2/save directory to /dir1/dir2. Basically, what I’m... (12 Replies)
Hello All,
Since i'm relatively new in shell script need your guidance.
I'm copying files manually based on a specific word in a file name and its extension and then moving it into some destination folder.
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Hello everyone, Im super new to coding but increasingly in need of it at work. Im have task stacked because of this problems, that I cannot figure out how to solve looking on the internet after trying many many things that looked similar to me.
I have multiple data files of the form (see below).... (2 Replies)
Discussion started by: Xfiles_fan
2 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)