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Top Forums Shell Programming and Scripting Using echo to print arguments inside a function Post 302881978 by drl on Friday 3rd of January 2014 10:10:32 AM
Old 01-03-2014
Hi.
Quote:
Originally Posted by kristinu
That is correct, the -e is treated as an option. I found it strange that echo is interpreting it as I put $@ in double quotes.
An illustration of $* and $@:
Code:
#!/usr/bin/env bash

echo
echo " asterisk"
echo "$*"

echo
echo " at sign"
echo "$@"

echo
echo " asterisk"
printf "%s\n" "$*"

echo
echo " at sign"
printf "%s\n" "$@"

producing:
Code:
$ ./s1 -e --example

 asterisk
-e --example

 at sign
--example

 asterisk
-e --example

 at sign
-e
--example

See man pages for details, and experiment.

Best wishes ... cheers, drl
 

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BOOLVAL(3)								 1								BOOLVAL(3)

boolval - Get the boolean value of a variable

SYNOPSIS
boolean boolval (mixed $var) DESCRIPTION
Returns the boolean value of $var. PARAMETERS
o $var - The scalar value being converted to a boolean. RETURN VALUES
The boolean value of $var. EXAMPLES
Example #1 boolval(3) examples <?php echo '0: '.(boolval(0) ? 'true' : 'false')." "; echo '42: '.(boolval(42) ? 'true' : 'false')." "; echo '0.0: '.(boolval(0.0) ? 'true' : 'false')." "; echo '4.2: '.(boolval(4.2) ? 'true' : 'false')." "; echo '"": '.(boolval("") ? 'true' : 'false')." "; echo '"string": '.(boolval("string") ? 'true' : 'false')." "; echo '"0": '.(boolval("0") ? 'true' : 'false')." "; echo '"1": '.(boolval("1") ? 'true' : 'false')." "; echo '[1, 2]: '.(boolval([1, 2]) ? 'true' : 'false')." "; echo '[]: '.(boolval([]) ? 'true' : 'false')." "; echo 'stdClass: '.(boolval(new stdClass) ? 'true' : 'false')." "; ?> The above example will output: 0: false 42: true 0.0: false 4.2: true "": false "string": true "0": false "1": true [1, 2]: true []: false stdClass: true SEE ALSO
floatval(3), intval(3), strval(3), settype(3), is_bool(3), Type juggling. PHP Documentation Group BOOLVAL(3)
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